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3 years ago

What fraction would represent the ratio of the cost

1 answer:

3 0

To write 3000 as a fraction you have to write 3000 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.
3000 = 3000/1 = 30000/10

And finally we have:
3000 as a fraction equals 30000/10

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Somebody please help

DaniilM [7]

Answer:

3/5x−3/7

Step-by-step explanation:

Simplify the expression.

3/5x−3/7

-hope it helps

6 0

2 years ago

How do i solve this question

Ludmilka [50]

Answer:

$a\frac{c}{8\pi b}$

Step-by-step explanation:

Divide both sides by $8\pi b$

$\frac{8\pi ab}{8\pi b} =\frac{c}{8\pi b}$

Simplify:

$a\frac{c}{8\pi b}$ ; $a\frac{c}{8\pi b}; b\neq 0$

8 0

3 years ago

A circle is divided into 9 uneven "pie" shaped pieces. Each section is labeled 1, 2, ... , 9. The circle is then spun and the nu

8_murik_8 [283]

There are three outcomes of 4 out of eighteen outcomes, so the fraction of angle of spinner numbered 4 is $\frac{3}{8}$

7 0

3 years ago

Read 2 more answers

12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5

Gnesinka [82]

$\large\underline{\sf{Solution-}}$

Given that,

In triangle TPQ, 

RS || PQ,

RS = 3 cm,

PQ = 6 cm,

ar(∆ TRS) = 15 sq. cm

As it is given that, RS || PQ

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

$\rm\implies \: \triangle TPQ \: \sim \: \triangle TRS \: \: \: \: \: \: \{AA \}$

Now, We know 

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)} = \dfrac{ {PQ}^{2} }{ {RS}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{ {6}^{2} }{ {3}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{36 }{9}$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = 4$

$\rm\implies \:ar( \triangle \: TPQ) = 60 \: {cm}^{2}$

3 0

2 years ago

To convert a quadratic from y = ax2 + bx + c form to vertex form, y = a(x - h)2+ k, you use the process of completing the square

ladessa [460]

Since we will be completing the square we need to isolate the x

y-5 = 2x^2 -4x

now we the coefficient of the x^2 to equal 1 so we take 2 as common factor

y-5 = 2(x^2 -2x)

now we'll make it perfect square by adding 2 to both sides

y-5+2=2(x^2-2x+1)

now simplify and convert the right side to squared expression

y-3 = 2(x-1)^2

now isolate the y

y = 2(x-1)^2 +3 that's it

5 0

3 years ago