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disa [49]
3 years ago
7

In the diagram, the length of segment QV is 15 units. What is the length of segment TQ?

Mathematics
1 answer:
GrogVix [38]3 years ago
5 0

Answer:

14 units is the answer

Step-by-step explanation:

^_^^_^^_^^_^^_^

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Complete the square to solve<br> LaTeX: 0=-x^2+4x-5<br> Also written as<br> 0= -x^2+4x-5
Feliz [49]
X=2+-(plus or minus)i
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3 years ago
For a club gathering you were having, you bought a total of 50 burgers, and spent $90. You paid $2 per turkey burger, and $1.50
Sedaia [141]

Answer:

<u></u>

  • <u>No. You would have to cut the number of veggie burgers in more than half.</u>

Explanation:

<u>1. Model the situation with a system of equations</u>

<u />

<u>a) Name the variables:</u>

  • number of turkey burgers: t
  • number of veggie burgers: v

<u />

<u>b) Number of burgers:</u>

  • 50 = t + v

<u />

<u>c) Cost of the 50 burgers:</u>

  • $90 = 2t + 1.50v

<u>2. Solve that system of equations:</u>

<u />

<u>a) System</u>

  • 50 = t + v
  • 90 = 2t + 1.50v

<u>b) Mutliply the first equation by 2 and subtract the second equation</u>

  • 100 = 2t + 2v
  •  90 = 2t + 1.50v

  • 10 = 0.5v
  • v = 20 ⇒ t = 50 - 20 = 30

<u />

<u>c) How much would you spend if the next year you buy the double of 20 turkey burgers (40) and the half of 30 veggie burgers (15)</u>

  • $2(40) + $1.50(15) = $80 + $22.50 = $102.50

Then, you if you double the number of turkey burgers, and cut the number burgers in half, you would spend more than $90 ($102.50).

6 0
3 years ago
The measurements of a triangle are given. Is there exactly one triangle that can be formed using the given measurements? If so,
NARA [144]

no, more than one triangle could be made with these measures

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6 0
3 years ago
Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.
Anuta_ua [19.1K]

Answer:

c

Step-by-step explanation:

First, we can transform this into a matrix. The x coefficients will be the first ones for each row, the y coefficients the second column, etc.

\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right]

Next, we can define a reduced row echelon form matrix as follows:

With the leading entry being the first non zero number in the first row, the leading entry in each row must be 1. Next, there must only be 0s above and below the leading entry. After that, the leading entry of a row must be to the left of the leading entry of the next row. Finally, rows with all zeros should be at the bottom of the matrix.

Because there are 3 rows and we want to solve for 3 variables, making the desired matrix of form

\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] for the first three rows and columns. This would make the equation translate to

x= something

y= something

z = something, making it easy to solve for x, y, and z.

Going back to our matrix,

\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right] ,

we can start by removing the nonzero values from the first column for rows 2 and 3 to reach the first column of the desired matrix. We can do this by multiplying the first row by -6 and adding it to the second row, as well as multiplying the first row by -1 and adding it to the third row. This results in

\left[\begin{array}{cccc}1&-2&3&-2\\0&14&-16&-36\\0&6&0&-36\end{array}\right]

as our matrix. * Next, we can reach the second column of our desired matrix by first multiplying the second row by (2/14) and adding it to the first row as well as multiplying the second row by (-6/14) and adding it to the third row. This eliminates the nonzero values from all rows in the second column except for the second row. This results in

\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&14&-16&-36\\0&0&96/14&-288/14\end{array}\right]

After that, to reach the desired second column, we can divide the second row by 14, resulting in

\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&1&-16/14&-36/14\\0&0&96/14&-288/14\end{array}\right]

Finally, to remove the zeros from all rows in the third column outside of the third row, we can multiply the third row by (16/96) and adding it to the second row as well as multiplying the third row by (-10/96) and adding it to the first row. This results in

\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&96/14&-288/14\end{array}\right]

We can then divide the third row by -96/14 to reach the desired third column, making the reduced row echelon form of the matrix

\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&1&-3\end{array}\right]

Therefore,

x=-5

y=-6

z=-3

* we could also switch the second and third rows here to make the process a little simpler

3 0
3 years ago
Does y varies directly with x? <br><br>Find the constant of variation and write the equation.​
amid [387]
Some textbooks describe direct variation by saying " y varies directly as x ", " y varies proportionally as x ", or " y is directly proportional to x . ") This means that as x increases, y increases and as x decreases, y decreases—and that the ratio between them always stays the same.
7 0
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