Answer:
1800
Step-by-step explanation:
→ First of all we need to find the prime factorisation of the numbers.
18 = 2 × 3 × 3 or 2 × 3²
40 = 2 × 2 × 2 × 5 or 2³ × 5
75 = 3 × 5 × 5 or 5² × 3
→ Now find the number that appear twice or more and write them down
3 and 3 from 18
2, 2 and 2 from 40
5 and 5 from 75
→ Now multiply all of these numbers together
3 × 3 × 2 × 2 × 2 × 5 × 5 = 3² × 2³ × 5² = 1800
Answer:
$1125000
Step-by-step explanation:
45,000 x 25 = 1125000
Since the question didn't specify what values to calculate, I will assume that it is how much money was issued in total.
8
d
8
d
out of
32
d
4
+
8
d
32
d
4
+
8
d
.
8
d
(
4
d
3
+
1
)
The answer is x = 6
To solve this you would use the pythagorean theorem which is a^2 + b^2 = c^2
In this problem a = x b = 8 and c = 10
You would then square these numbers
x^2 + 64 = 100
Next, you would subtract 64 from both sides.
x^2 = 36
All that’s left is the find the square root, which is x = 6.
So, therefore, you’re answer is x = 6
Answer: Yes, you can use this inequality to find the numbers of cars required.
Step-by-step explanation:
12 + 3n > 28 where n = the number of cars required
3n > 28 -12
3n > 16
n > 5 1/3
Greater than 5 1/3 gives 6 cars.
