If the width of the garden is w, then the maximum area available is a square, giving you w² as the dimensions. So:
w²=-w²+28w
2w²=28w
w=14
The perimeter is 14 x 4, or 56 feet
How many seed packets??? No idea
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For the problem are you supposed to be solving for x
at least 4 different angles are present
Y -:5 = 2/3x + 6 because 6 is 2/3 of 9
add 5 to both sides
y - 5 +:5 = 2/3x + 6 + 5
y = 2/3x + 11
the y intersept is 11 or (0 , 11) when x is 0
when x is 3
y = 2/3 (3) + 11 or 2 + 11 = 13
so a 2nd point could be (3 , 13)
