HELP PLEASE
1 answer:
Using a graph tool
case 1)
2x-y=-13
y=x+9
the solution is the point (-4,5)
see the attached figure N 1
case 2)
y=3x-7
y=2x-5
the solution is the point (2,-1)
see the attached figure N 2
case 3)
3x+2y=10
6x-y=10
the solution is the point (2,2)
see the attached figure N 3
case 4)
y=6
x=-5
the solution is the point (-5,6)
see the attached figure N 4
case 5)
4x-3y=5
3x+2y=-9
the solution is the point (-1,-3)
case 6)
x+y=7
x-y=-1
the solution is the point (3,4)
the answer in the attached figure
case 1)
2x-y=-13
y=x+9
the solution is the point (-4,5)
see the attached figure N 1
case 2)
y=3x-7
y=2x-5
the solution is the point (2,-1)
see the attached figure N 2
case 3)
3x+2y=10
6x-y=10
the solution is the point (2,2)
see the attached figure N 3
case 4)
y=6
x=-5
the solution is the point (-5,6)
see the attached figure N 4
case 5)
4x-3y=5
3x+2y=-9
the solution is the point (-1,-3)
case 6)
x+y=7
x-y=-1
the solution is the point (3,4)
the answer in the attached figure
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9514 1404 393
Answer:
26 square feet
Step-by-step explanation:
When two of the trapezoids are combined to make a parallelogram, the height remains the same (4 ft), but the width is the sum of the base lengths, 10 ft + 3 ft = 13 ft.
The area of the combined trapezoids is ...
A = bh = (13 ft)(4 ft) = 52 ft^2
The area of one trapezoid is half that, so is ...
A = (52 ft^2)/2 = 26 ft^2 . . . . area of the trapezoid
