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NikAS [45]
3 years ago
14

Match the probability formula with the correct probability name.

Mathematics
1 answer:
steposvetlana [31]3 years ago
5 0

Answer:

a. independent event  P(AuB)=P(A)+P(B)

b. mutually exclusive event  P(AuB) = P(A) + P(B) - P(AnB)

c.  independent event P(A and B) = P(A).P(B)

d.   complement P(A') = 1 - P(A)

Step-by-step explanation:

a. For two events A and B the union of the two sets is  simply all the elements present in both set. This can be expressed as

P(AuB)=P(A)+P(B)

b. Two events are said to be mutually exclusive if they cannot occur at the same time. i.e no same element must be present in both events at a time. This can be expressed as

P(AuB) = P(A) + P(B) - P(AnB)

c.  event A and event B are said to be independent if the incidence of event A  does not affect the probability of the event B.

This can be expressed as

P(A and B) = P(A).P(B)

d. complement of an event are simply all the occurrence not in he set but in the universal set.

the complement of set A can be expressed as

 P(A') = 1 - P(A)

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If the vertex of a parabola is (0, 3), what is the axis of symmetry
GREYUIT [131]

Answer:

The equation of the axis of symmetry for this parabola is x = 0.

Step-by-step explanation:

For parabola's, it's axis of symmetry always goes through the vertex of the parabola. In other words, the axis of symmetry is vertical line that goes through the x-coordinate of the vertex.

Now, the vertex is given as (0,3) which is at x = 0, y = 3.

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Thus, the equation of the axis of symmetry for this parabola is x = 0.

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\huge\mathrm{Answer࿐}

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To remove √3 from denominator, we multiply both numerator as well as denominator with √3

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Y+2 = -3(x – 4)<br> Complete the missing value in the solution to the equation. <br><br> (?, -2)
ss7ja [257]

Answer:

The missing value in the solution to

the equation will be:

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Step-by-step explanation:

Given the equation

y+2\:=-3\left(x\:-\:4\right)

As the value of y = -2 is given.

so substituting the value y = -2 in the equation to find the missing value

\left(-2\right)+2\:=-3\left(x\:-\:4\right)

switch the sides

-3\left(x-4\right)=\left(-2\right)+2

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

-3\left(x-4\right)=-2+2

-3\left(x-4\right)=0

\mathrm{Divide\:both\:sides\:by\:}-3

\frac{-3\left(x-4\right)}{-3}=\frac{0}{-3}

x-4=0

x=4

Therefore, the missing value in the solution to

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3 years ago
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