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Vlad1618 [11]
3 years ago
9

Veronica has been saving dimes and quarters she has 110 coins in all and the total value is 18.50 how many dimes and quarters do

es she have ?​
Mathematics
1 answer:
Lady_Fox [76]3 years ago
6 0

This problem can be solved by the chicken rabbits method or you can just do simple algebra.

I.) Chicken and rabbits method

First assume all 110 coins are dimes and none are quarters.

We will have a total value of 11 dollars

Now for each dime we switch out for a quarter, we adds 15 cents to the total value.

18.50-11=7.50 dollars

There are 750/15=50 group of 15 cents in the 7 dollars and 50 cents.

This also meant that we need to switch out 50 dimes for 50 quarters.

So we have 50 quarters.

That first method is very good and very quick once you get the hang of it, now I'm going to show you the algebraic way to solve this.

Let's say there are x dimes and y quarters.

Set up equation

x+y=110

10x+25y=1850

Now solve multiply first equation by 10

10x+10y=1100

subtract

15y=750

y=50

Now we set the numbers of quarters to y so the answer is 50 quarters.

I personally recommend using algebra whenever you can because the practice is very important and you will eventually get really fast at setting up and solving equations. The first method is faster in this case but the second is more generalize, hope it helps.

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F is directly proportional to a . If F = 24 when a = 8 find, F when a = 6
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2 years ago
An accounting firm is trying to decide between IT training conducted in-house and the use of the third party consultants. To get
Jlenok [28]

Answer:

t=\frac{500-490}{\sqrt{\frac{48^2}{180}+\frac{32^2}{210}}}}=2.379  

p_v =2*P(t_{388}>2.379)=0.0178

Comparing the p value with the significance level provided \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and a would be a significant difference in the average of the two groups.  

Step-by-step explanation:

Assuming the following info

IT Training     N   mean Stdev

In-house       210 $490 $32

Consultants  180 $500 $48

1) Data given and notation

\bar X_{I}=490 represent the mean for the sample of In-house

\bar X_{C}=500 represent the mean for the sample Consutants

s_{I}=32 represent the population standard deviation for the sample In-house

s_{C}=48 represent the population standard deviation for the sample Consultants

n_{I}=210 sample size for the group In-house

n_{C}=180 sample size for the group Consultants

t would represent the statistic (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the means for the two groups are the same, the system of hypothesis would be:

Null hypothesis:\mu_{I}=\mu_{C}

Alternative hypothesis:\mu_{I} \neq \mu_{C}

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{C}-\bar X_{I}}{\sqrt{\frac{s^2_{C}}{n_{C}}+\frac{s^2_{I}}{n_{I}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

3) Calculate the statistic

With the info given we can replace in formula (1) like this:

t=\frac{500-490}{\sqrt{\frac{48^2}{180}+\frac{32^2}{210}}}}=2.379  

4) Statistical decision

First we need to calculate the degrees of freedom given by:

df=n_{C}+n_{I}-2=210+180-2=388[/tex[The sample is large enough to assume that the distribution is also normal.Since is a bilateral test the p value would be:
[tex]p_v =2*P(t_{388}>2.379)=0.0178

Comparing the p value with the significance level provided \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and a would be a significant difference in the average of the two groups.  

6 0
4 years ago
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