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3 years ago

What is 54/72 in simplest form?

Mathematics

1 answer:

KonstantinChe [14]3 years ago

5 0

The answer is 3/4. You divide both numbers (54 and 72) by 18 and you get 3/4. Hope it helps!

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The picture frame has a perimeter of 100 inches. The width is 22 inches. Calculate the missing length. Use that answer to find t

ivanzaharov [21]

Answer:

39 inches.

858 inches²

Step-by-step explanation:

Length:- (if length = x)

2 ( 11 + x ) = 100

22 + 2x = 100

2x = 100 - 22

2x = 78

x = 78 ÷ 2

x = 39 inches

Area:-

Area = l × b

= 39 × 22

= 858 inches²

8 0

2 years ago

Is this correct and if not can you please correct it!

Tanzania [10]

Answer:

Correct!

Step-by-step explanation:

That’s right

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2 years ago

Ms. Johnson earns $47,000 per year. She is paid weekly and puts 8% of her salary

Gekata [30.6K]

You divide 47,000 by 8. You should get 5,875. That should be the answer

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2 years ago

Consider the following hypothesis test. H0: μ ≥ 55 Ha: μ < 55 A sample of 36 is used. Identify the p-value and state your con

Ket [755]

Answer:

Step-by-step explanation:

Given that:

$H_o: \mu \ge 55 \ \\ \\ H_1 : \mu < 55$

(a) For x = 54 and s = 5.3

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{54-55}{\dfrac{5.3}{\sqrt{36}} }$

$Z = \dfrac{-1}{\dfrac{5.3}{6} }$

Z = -1.132

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-1.132,35,1) = 0.1326

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

For x = 53 and s = 4.6

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{53-55}{\dfrac{4.6}{\sqrt{36}} }$

$Z = \dfrac{-2}{\dfrac{4.6}{6} }$

Z = -2.6087

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-2.6087,35,1) =0.0066

Decision: p-value is < significance level; we reject the null hypothesis.

$Conclusion: \ There \ is \ sufficient \ evidence \ to \ conclude \ that$ $\mu < 55$

For x = 56 and s = 5.0

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }$

Z = 1.2

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(1.2,35,1) = 0.88009

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

6 0

2 years ago

If you on a motorcycle trip of 30 miles in the and 5\19 of the trip is downhill, how many miles of the trip are not downhill? Re

Bess [88]

Answer:

1/4 of the trip is not down hill

8 0

2 years ago