Answer:
2x^2-6x-4
Step-by-step explanation:
(7x2 + 4x - 9)
-(5x2 + 10x - 5)
=
7x^2-5x^2=2x^2
4x-10x=-6x
-9-(-5)=-4
thus, your answer is 2x^2-6x-4
You most likely only need the first 3 digits after the decimal point but if you needed more i added them! hope this helps
$123.75 you would round all of them to the nearest hundreth
The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.
Solve for the hypotenuse of the right triangle formed.
h = sqrt((-1)² + (1)²) = √2
Below items show the calculation for each of the trigonometric functions.
sin θ = opposite/hypotenuse = y/h = (-1)/(√2) = -√2/2
cos θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
tan θ = opposite/adjacent = y/x = -1/1 = -1
The domain is the same as the x value and the range is the same as the y value, so you just plug in the 3 to all the x's.
the range of the function is 17
