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zalisa [80]
2 years ago
10

In which of the following phases of filmmaking would a production team be focused on the

Computers and Technology
2 answers:
Anettt [7]2 years ago
7 0
I think it’s pre production! Goodluck :)
Marina CMI [18]2 years ago
7 0

Answer:

Pre-Production

Explanation:

Once the film concept has been developed, the film company transitions to the production phases: pre-production, production, and post-production. In pre-production, the technical details are worked out, a schedule is set, and the resources to produce the film are assembled. This includes casting the film, filling the technical positions, and scheduling the production. The actual filming takes place during the production phase, followed by a post-production phase in which the footage is edited and the final film emerges.

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Find the maximum value and minimum value in milesTracker. Assign the maximum value to maxMiles, and the minimum value to minMile
ryzh [129]

Answer:

Following are th program in the C++ Programming Language.

#include <iostream>//set Header files

using namespace std;//set namespace

//define main function

int main()

{

//set integer constants variable

const int NUM_ROWS = 2;

//set integer constants variable

const int NUM_COLS = 2;

//set integer type array

int milesTracker[NUM_ROWS][NUM_COLS];

//set integer type variable and initialize to 0

int i = 0;

//set integer type variable and initialize to 0

int j = 0;

//set integer type variable and initialize to -99

int maxMiles = -99;

//set integer type variable and initialize to -99

int minMiles = -99;

//initialize the value in the two dimensional array

milesTracker[0][0] = -10;

milesTracker[0][1] = 20;

milesTracker[1][0] = 30;

milesTracker[1][1] = 40;

//here is the solution  

maxMiles = milesTracker[0][0];

minMiles = milesTracker[0][0];

/*set for loop to find the minimum miles and maximum miles*/

for (i = 0; i < NUM_ROWS; i++)

{

 for (j = 0; j < NUM_COLS; j++)

 {

 //set if condition for maxMiles is the bigger than

   if (milesTracker[i][j] > maxMiles)

   //initialize milesTracker[i][j] to maxMiles

     maxMiles = milesTracker[i][j];

   //set if condition for minMiles is the smaller than

   if (milesTracker[i][j] < minMiles)

   //initialize milesTracker[i][j] to maxMiles

     minMiles = milesTracker[i][j];

 }

}

//print output

cout << "Min miles: " << minMiles << endl;

//print output

cout << "Max miles: " << maxMiles << endl;

return 0;

}

<u>Output:</u>

Min miles: -10

Max miles: 40

Explanation:

Here, we define the main method and inside it:

  • set two constant integer type variable and initialize to 2
  • set integer type two-dimensional array and pass constant variables in it.
  • Set two integer type variable and initialize to 0 then, again set two integer type variable and initialize to -99.
  • Initialize the values in the two-dimensional array.
  • Set two for loop for the two-dimensional array to find the minimum and maximum miles.
  • Set two if condition to find bigger or smaller miles.

Finally, print the maximum and the minimum miles then, return 0.

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3 years ago
Compare GBN, SR, and TCP (no delayed ACK). Assume that the timeout values for all three protocols are sufficiently long such tha
kvv77 [185]

Answer and Explanation:

a)

For Go-Back-N:

  Host A sent total number of segments is 9.The initial segment numbers are 1,2,3,4,5 and re-sent the segemnts 2,3,4 and 5 because 2nd segment was lost.

Host B sent the number of ACKs are 8.Host B sent ACKs 1 by four times because 2nd segment was lost and sent 4ACKs with sequence numbers 2,3,4 and 5

selective repeat:

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Host B sent the number of ACKs are 5.Host B sent four ACKs with sequence numbers 1,3,4,5 and re-sent ACK2 with sequence number 2 because 2nd segment was lost.

TCP :

Host A sent total number of segments is 6.The initial segment numbers are 1,2,3,4,5 and re-sent the segemnts 2 because 2nd segment was lost.

Host B sent the number of ACKs are 5.Host B sent four ACKs with sequence number 2 and There is one ACK with sequence number 6.TCP always send an ACK with expected sequence number

b) If the timeout values for all three protocol are much longer than 5*RTT,then TCP protocol successfully delivers all five data segments in shortest time interval.

 

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An output device is any device that displays, prints, or plays content stored on a computer. from the list below, identify the d
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Answer is C = Speaker

How? as the speaker is the only item on the list that displays any type of content, that being audio, it's the only feasible answer to this question.
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Assuming Victoria is using Adobe Photoshop to create her brochure, below are the steps she is required to follow.

She should first open the image on Photoshop, click on the image option and select duplicate just in case the resized image is not what she wants.

Still on the image option, she should select Image size. A screen will pop up at this point, indicating the image’s current size. For the purposes of image resizing, Victoria should select Pixel dimensions category.

She should be able to type her preferred dimensions for both the width and height. She should make sure ‘Constrain Proportions’ is unchecked to be able to type in separate values.

If she decides to use the photo editing program, she can simply click on the image, and if resize handles appear around it, she can click and drag those to the desired size.


3 0
3 years ago
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