Discuss the difference between a broad internet search and a narrow internet search?
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PYTHON CODE
# function to compare a and b
def compare(a,b):
# if a is greater than b , return 1
if a > b:
return 1
# if a and b are equal, return 0
elif a == b:
return 0
# if a less than b , return -1
elif a < b :
return -1
# testing
if __name__=="__main__":
# calling the compare function with a and b
print('compare(5,2) %d'%compare(5,2))
print('compare(2,5) %d'%compare(2,5))
print('compare(3,3) %d'%compare(3,3))
# getting values for a and b
a=int(input("Enter the value for a: "))
b=int(input("Enter the value for b: "))
print('compare(%d,%d) %d'%(a,b,compare(a,b)))
(see attachment for output)
Solution :
#include
#include
#include
//Converts to binary string.
* hexadecimal
Binary(char* hexdec)
{
long = 0;
char *string = (sizeof(char) * 9);
while (hexdec[i]) {
//Simply assign binary string for each hex char.
switch (hexdec[i]) {
strcat(string, "0000");
break;
strcat(string, "0001");
break;
strcat(string, "0010");
break;
strcat(string, "0011");
break;
strcat(string, "0100");
break;
strcat(string, "0101");
break;
strcat(string, "0110");
break;
strcat(string, "0111");
break;
strcat(string, "1000");
break;
strcat(string, "1001");
break;
case 'A':
case 'a':
strcat(string, "1010");
break;
case 'B':
case 'b':
strcat(string, "1011");
break;
case 'C':
case 'c':
strcat(string, "1100");
break;
case 'D':
case 'd':
strcat(string, "1101");
break;
case 'E':
case 'e':
strcat(string, "1110");
break;
case 'F':
case 'f':
strcat(string, "1111");
break;
default:
printf("\nInvalid hexadecimal digit %c",
hexdec[i]);
string="-1" ;
}
i++;
}
return string;
}
int main()
{ //Take 2 strings
char *str1 =hexadecimalToBinary("FA") ;
char *str2 =hexadecimalToBinary("12") ;
//Input 2 numbers p and n.
int p,n;
scanf("%d",&p);
scanf("%d",&n);
//keep j as length of str2
int j=strlen(str2),i;
//Now replace n digits after p of str1
for(i=0;i<n;i++){
str1[p+i]=str2[j-1-i];
}
//Now, i have used c library strtol
long ans = strtol(str1, NULL, 2);
//print result.
printf("%lx",ans);
return 0;
}