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2 years ago

Which of the following is considered to be intellectual property?

1 answer:

4 0

The answer is actually A. I took the test and selected the wrong answer, but A was the one the test said was right. Plz mark brainliest!!! Hope this helped! ;^)

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What role does javascript play in a web page

luda_lava [24]

Answer:

Js is an programming language usually used for coding. It is used on most browsers to produce an effective and interactive design for some users.

6 0

2 years ago

Show me how to create an argument essayshow me how to create an argument essay

Lady_Fox [76]

Answer:

1 Introduce the problem.

2 Explain your perspective.

3 Explain your opponent's perspective. Refute their points one-by-one as you go.

4 Present your evidence.

5 Conclude your argument.

1 Introduce the problem.

2 Explain your opponent's perspective first. ...

3 Explain your perspective.

Explanation:

3 0

2 years ago

17.8.1: Writing a recursive math function. Write code to complete raise_to_power(). Note: This example is for practicing recursi

Yuliya22 [10]

Answer:

The recursion function is as follows:

def raise_to_power(num, power):

if power == 0:

return 1

elif power == 1:

return num

else:

return (num*raise_to_power(num, power-1))

Explanation:

This defines the function

def raise_to_power(num, power):

If power is 0, this returns 1

if power == 0:

return 1

If power is 1, this returns num

elif power == 1:

return num

If otherwise, it calculates the power recursively

else:

return (num*raise_to_power(num, power-1))

6 0

3 years ago

1. How many bits would you need to address a 2M × 32 memory if:

Dominik [7]

Answer:

a) 23 b) 21
a) 43 b) 42
a) 0 b) 0

Explanation:

1) How many bits is needed to address a 2M * 32 memory

2M = 2^1*2^20, while item =32 bit long word

hence ; L = 2^21 ; w = 32

a) when the memory is byte addressable

w = 8; L = ( 2M * 32 ) / 8 = 2M * 4

hence number of bits = log2(2M * 4)= log2 ( 2 * 2^20 * 2^2 ) = 23 bits

b) when the memory is word addressable

W = 32 ; L = ( 2M * 32 )/ 32 = 2M

hence the number of bits = log2 ( 2M ) = Log2 (2 * 2^20 ) = 21 bits

2) How many bits are required to address a 4M × 16 main memory

4M = 4^1*4^20 while item = 16 bit long word

hence L ( length ) = 4^21 ; w = 16

a) when the memory is byte addressable

w = 8 ; L = ( 4M * 16 ) / 8 = 4M * 2

hence number of bits = log 2 ( 4M * 2 ) = log 2 ( 4^1*4^20*2^1 ) ≈ 43 bits

b) when the memory is word addressable

w = 16 ; L = ( 4M * 16 ) / 16 = 4M

hence number of bits = log 2 ( 4M ) = log2 ( 4^1*4^20 ) ≈ 42 bits

3) How many bits are required to address a 1M * 8 main memory

1M = 1^1 * 1^20 , item = 8

L = 1^21 ; w = 8

a) when the memory is byte addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

hence number of bits = log 2 ( 1M ) = log2 ( 1^1 * 1^20 ) = 0 bit

b) when memory is word addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

number of bits = 0

5 0

2 years ago

Which strategies for effective presentations is Ian using in his opening? Check all that apply.

Fofino [41]

Answer:

A. using a hook in his opening

B. detailing the speech’s objectives

E. letting his audience know what to expect

Explanation:

Opening his speech using a quotation is a strategy of using a narrative hook, or simply hook, by Ian. Giving a grand and enticing opening is what makes an audience to pay attention and listen to what the speaker has to say in his speech. So, first strategy used by Ian is using a hook in his opening.

Another strategy used by Ian is giving objective details of his speech. By outlining what he will be covering in his speech, Ian is letting his audience know what to expect from the speaker and his speech, and also gave details of his speech.

So, option A, B, and E are correct.

5 0

3 years ago

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