Answer:
Given the sequence of DNA bases sequence:
- <em>DNA </em><em>TAC GAG TTG CCG TAT ATT GCG CTC GAC TGC</em><em>
</em>
Transcription into mRNA and translation would be:
- <em>mRNA </em><em>AUG CUC AAC GGC AUA UAACGC GAG CUG ACG
</em>
- <em>Amino acids </em><em>Met (Start)-Leu-Asn-Gly-Ile-Stop-Arg-Glu-Leu-Thr</em>
Explanation:
Genetic information is found in DNA, and this information depends on a sequence of bases —adenine, thymine, cytosine and guanine— in the DNA molecule.
Transcription consists of creating a strand of mRNA, from the sequence of bases in a DNA strand, which it assumes:
- <em>The sequence of RNA is complementary to the DNA sequence that forms it, following the complementarity of bases.
</em>
- <em>In RNA there is no base thymine, which is replaced by uracil.
</em>
The sequence of mRNA is organized into triplets or codons, each of which encodes for the synthesis of an amino acid (translation), indicating both the start of a polypeptide chain and the stop of protein synthesis. Knowing this information, it can be stated that, following a sequence of DNA bases, the resulting transcription and translation would be:
- <em>DNA </em><em>TAC GAG TTG CCG TAT ATT GCG CTC GAC TGC</em><em>
</em>
- <em>Transcription </em><em>AUG CUC AAC GGC AUA UAACGC GAG CUG ACG
</em>
- <em>Translation </em><em>Met (Start)-Leu-Asn-Gly-Ile-Stop-Arg-Glu-Leu-Thr</em>
Resulting amino acids and indications in protein synthesis Methionine (inicio), Leucine, Asparagine, Glycine, Isoleucine —Stop— Arginine, Glutamine, Leucine and Tyrosine.