X^2 + 5 = 5 + x^2 will give you the same answer. Also know as the commutative property. Answer is (3)
So cancel each equation terms on both sides of the equation and move constant to the right side and change its sign. So your answer is A=-3
Your welcome
Answer:
115% of 75 is equivalent to 75 by 1.15 = 8.625 , This two are equivalent
Step-by-step explanation:
Given as :
Tyson multiplies 75 by 1.15
I .e 75 × 1.15 = 86.25
Now A ) 115% of 75 =
× 75 = 86.25
B) 15% of 75 =
× 75 = 11.25
C) 11.5% of 75 =
× 75 = 8.625
D) 1.15% of 75 =
× 75 = 0.8625
∵ 115% of 75 is equivalent to 75 by 1.15 , so Tyson try to find the option A
Answer
Answer: About
Step-by-step explanation:
The missing figure is attached.
Notice in the first picture that Alberta has a complex shape.
You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.
Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.
The area of the trapezoid can be calcualted with the formula:
![A_t=\frac{h}{2}(B+b)](https://tex.z-dn.net/?f=A_t%3D%5Cfrac%7Bh%7D%7B2%7D%28B%2Bb%29)
Where "h" is the height, "B" is the long base and "b" is short base.
And the area of the rectangle can be found with the formula:
![A_r=lw](https://tex.z-dn.net/?f=A_r%3Dlw)
Wkere "l" is the lenght and "w" is the width.
Then, the apprximate area of Alberta is:
![A=\frac{h}{2}(B+b)+lw](https://tex.z-dn.net/?f=A%3D%5Cfrac%7Bh%7D%7B2%7D%28B%2Bb%29%2Blw)
Substituting vallues, you get:
![A=(\frac{(410\ mi-180\ mi)}{2})(760\ mi+470\ mi)+(180\ mi)(760\ im)\\\\A=141,450\ mi^2+136,800\ mi^2\\\\A=278,250\ mi^2](https://tex.z-dn.net/?f=A%3D%28%5Cfrac%7B%28410%5C%20mi-180%5C%20mi%29%7D%7B2%7D%29%28760%5C%20mi%2B470%5C%20mi%29%2B%28180%5C%20mi%29%28760%5C%20im%29%5C%5C%5C%5CA%3D141%2C450%5C%20mi%5E2%2B136%2C800%5C%20mi%5E2%5C%5C%5C%5CA%3D278%2C250%5C%20mi%5E2)
Therefore, the area of of Alberta is about
.