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2 years ago

Can someone help me on all of them I would appreciate it so much!

Mathematics

1 answer:

katovenus [111]2 years ago

3 0

I hope this helps !!

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in my fish tank the ratio of the redfish to bluefish is 3:5 there are 20 bluefish how many red fish are there

qwelly [4]

Let x be the number of red fish
3:5 = x:20
3/5 = x/20
(Cross method)
5x = 60
x =12

There are 12 red fish in the fish tank.

7 0

2 years ago

Please help with this

N76 [4]

$VWX\cong KLJ$ means that the triangles are congruent, that is exactly identical.

The order of letters is very important. Form the given congruence we can write the following ratio:

$\frac{VW}{KL} = \frac{WX}{LJ} = \frac{VX}{KJ} =1$

(notice that we do not mix the order: the first 2 letters of VWX are compared to the first 2 letters of KLJ and so on)

the ratio is one because the corresponding sides are equal.

$\frac{VW}{KL}=1\\\\ \frac{2z-1}{z+2}=1\\\\2z-1=z+2\\\\2z-z=2+1\\\\z=3$

$|VW|=2z-1=2.3-1=6-1=5$

Answer: 5 units

8 0

3 years ago

Two trucks are driving to the same place. The first truck starts 50 miles ahead of the second truck and travels at an average sp

Dominik [7]

Well obviously the two bottom graphs don't represent the two trucks meeting. So we can cross those out. Looking at the top two graphs we can tell that the line above is truck #2. In graph 1 it shows the second truck is slowing down which is wrong since that isn't told.

So the answer would be Graph #2

I hope this helps!

-Ayden

5 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2B%5Cfrac%7B1%7D%7B3%7D" id="TexFormula1" title="\frac{1}{2} +\frac{1

iren [92.7K]

Answer:

$\frac{1}{2} + \frac{1}{3} = \frac{5}{6}$

Step-by-step explanation:

1/2+1/3 L.C.M = 6

$\frac{3 + 2}{6} = \frac{5}{6}$

4 0

2 years ago

Which statement is true about point F? a.F is the midpoint of AA' because bisects AA'. b.F is the midpoint of EG because AA' bis

Dimas [21]

Answer:

The correct option is;

a. F is the midpoint of $\overline{AA'}$ because line $\overline{EG}$ bisects $\overline{AA'}$

Step-by-step explanation:

Here, since we have that the triangle is reflected across EG therefore the location of the point F which is along EG bisects the line $\overline{AA'}$ as the dimensions of the line from A to F must be equal to the dimension of the line that extends from A' to F

Therefore the point F is the midpoint of $\overline{AA'}$ because line $\overline{EG}$ bisects $\overline{AA'}$ .

7 0

3 years ago