82, because the rest are perfect squares
First, we'll solve A.
2 x2 = 4
3 x2 = 9
3x2=6, not 9.
So it is not A.
5 x2 = 10
7 x2 = 11
7x2=14, not 11.
So B. is out too.
It isn't D. because 12/9 is improper and 3/4 isn't.
So C. is left.
4 x2 = 8
6 x2 = 12
hope it helps!
Use the difference of squares factorization - that for any numbers a and b, (a-b)(a+b)=a^2-b^2.
We have:
(x^2+1)(x^2-1)=x^4-1
In addition:
(x-1)(x+1)=x^2-1, so we have:
(x^2+1)(x+1)(x-1)
As our complete factorization.
Line segment is limited by two endpoints which also define one.
A Line is not limited to but only exists because of those two endpoints.
Hope this helps.
Answer:
b
Step-by-step explanation: