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harina [27]
3 years ago
9

Tickets to the school dance cost $3.00 in advance or $5.00 at the door. There were a total of 184 tickets sold, raising $688. Ho

w many tickets were sold at the door?
Mathematics
1 answer:
GenaCL600 [577]3 years ago
5 0
Answer: They sold 68 tickets at the door
688-920= -2x= -232
2x=232/2=116
184-116=68
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I Really Need Help!!!!! :)
DerKrebs [107]

Answer:

Hence first graph is the correct answer.

T I

1 28

2 56

3 84

4 112

Step-by-step explanation:

Given that initial amount P = $400

Simple rate of interest = R = 7% = 0.07

Time t= 1,2,3,4 years.

Then apply Simple interest formula to find the total interest earned in the given years.

I=PRT

for t=1 year

I=PRT=400(0.07)(1)=28

for t=2 year

I=PRT=400(0.07)(2)=56

for t=3 year

I=PRT=400(0.07)(31)=84

for t=4 year

I=PRT=400(0.07)(4)=112

Now we have table as shown below:

T I

1 28

2 56

3 84

4 112

Graphing these points we see that obtained graph best matches with First choice .

Hence first graph is the correct answer.

7 0
3 years ago
Let log_(b)A=3; log_(b)C=2; log_(b)D=5 what is the value of log_(b)((A^(5)C^(2))/(D^(6)))
Colt1911 [192]

Answer:

-11

Step-by-step explanation:

Given

\log_bA=3\\ \\\log_bC=2\\ \\\log_bD=5

Use properties:

\log_b(A\cdot C)=\log_bA+\log_bC\\ \\\log_b\dfrac{A}{C}=\log_bA-\log_bC\\ \\\log_bA^k=k\log_bA

Thus,

\log_b\dfrac{A^5\cdot C^2}{D^6}\\ \\=\log_b(A^5\cdot C^2)-\log_bD^6\\ \\=\log_bA^5+\log_bC^2-\log_bD^6\\ \\=5\log_bA+2\log_bC-6\log_bD\\ \\=5\cdot 3+2\cdot 2-6\cdot 5\\ \\=15+4-30\\ \\=-11

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3 years ago
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Gre4nikov [31]
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3 years ago
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Find the area of the figure. If needed, round to the nearest tenth.
Umnica [9.8K]

Answer:

18 \:ft^2

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