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MrMuchimi
3 years ago
12

Observe randomly the weight of 100 chickens at farm A. The sample mean is 3.4 kg and sample standard deviation is 0.5. Observe r

andomly the weight of 200 chickens at farm B. The sample mean is 4.1 kg and sample standard deviation is 0.9. With the significance level of 2%, can we conclude that the true average weight of farm A is something other than farm B ?
Mathematics
1 answer:
attashe74 [19]3 years ago
4 0

Answer:

40 percent goes to farmers so hipe it

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A formula is expressed as d=a(2+kt). Express k in terms of d, a and t
taurus [48]
<span>Answer:
k = </span>\frac{d-2a}{at} =  \frac{d}{at} -  \frac{2a}{at} =  \frac{d}{at} - \frac{2}{t}<span>

Explanation:
To get the value of k, we will need to isolate it on one side of the equation.
This can be done as follows:
d = a(2+kt)

<u><em>1- get rid of the brackets using distributive property:</em></u>
d = a(2+kt)
d = 2a + akt

<u><em>2- Subtract 2a from both sides of the equation:</em></u>
d - 2a = 2a + akt - 2a
d - 2a = akt

<u><em>3- Divide both sides of the equation by "at":</em></u>
</span>\frac{d-2a}{at} = \frac{akt}{at}<span> 

</span>k= \frac{d-2a}{at}
<span>
<u><em>4- We can further simplify the answer as follows:</em></u>
</span>k = \frac{d-2a}{at} = \frac{d}{at} - \frac{2a}{at} = \frac{d}{at} - \frac{2}{t}
<span>
Hope this helps :)</span>
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3 years ago
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