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3 years ago

Estimate the product of 26.4×2.7

Mathematics

2 answers:

Solnce55 [7]3 years ago

4 0

Answer:..

Step-by-step explanation:

Julli [10]3 years ago

3 0

Answer:

Step-by-step explanation:

okay, 26.4*2.7 = 26*3 (when estimated)

26*3=78(or just somewhere around 70)

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Please help me I would really appreciate it this really affects my grade need the answer the ASAP

Drupady [299]

Answer:

27/6, 4 3/6, or simplified version 4 1/2

Step-by-step explanation:

Always convert the mixed numbers into an improper fraction before you solve, this makes it easier to solve.

2 4/6 = 16/6

1 5/6 = 11/6

3 4/6 = 22/6

Now we solve. Remember, you do NOT add the denominator, leave it as 6 not 12. You only add the numerator.

16/6 + 11/6 = 27/6, 4 3/6 or simplified as 4 1/2

22/6 + 5/6 = The same as above.

6 0

4 years ago

HELP ILL GIVE YOU BRAINLIEST ‼️‼️‼️‼️

Sladkaya [172]

Answer:

36 200 a-c = 36 for 200 and that is how it's done

5 0

3 years ago

Suppose that a spherical droplet of liquid evaporates at a rate that is proportional to its surface area: where V = volume (mm3

Alex

Answer:

V = 20.2969 mm^3 @ t = 10

r = 1.692 mm @ t = 10

Step-by-step explanation:

The solution to the first order ordinary differential equation:

$\frac{dV}{dt} = -kA$

Using Euler's method

$\frac{dVi}{dt} = -k *4pi*r^2_{i} = -k *4pi*(\frac {3 V_{i} }{4pi})^(2/3)\\ V_{i+1} = V'_{i} *h + V_{i} \\$

Where initial droplet volume is:

$V(0) = \frac{4pi}{3} * r(0)^3 = \frac{4pi}{3} * 2.5^3 = 65.45 mm^3$

Hence, the iterative solution will be as next:

i = 1, ti = 0, Vi = 65.45

$V'_{i} = -k *4pi*(\frac{3*65.45}{4pi})^(2/3) = -6.283\\V_{i+1} = 65.45-6.283*0.25 = 63.88$

i = 2, ti = 0.5, Vi = 63.88

$V'_{i} = -k *4pi*(\frac{3*63.88}{4pi})^(2/3) = -6.182\\V_{i+1} = 63.88-6.182*0.25 = 62.33$

i = 3, ti = 1, Vi = 62.33

$V'_{i} = -k *4pi*(\frac{3*62.33}{4pi})^(2/3) = -6.082\\V_{i+1} = 62.33-6.082*0.25 = 60.813$

We compute the next iterations in MATLAB (see attachment)

Volume @ t = 10 is = 20.2969

The droplet radius at t=10 mins

$r(10) = (\frac{3*20.2969}{4pi})^(2/3) = 1.692 mm\\$

The average change of droplet radius with time is:

Δr/Δt = $\frac{r(10) - r(0)}{10-0} = \frac{1.692 - 2.5}{10} = -0.0808 mm/min$

The value of the evaporation rate is close the value of k = 0.08 mm/min

Hence, the results are accurate and consistent!

5 0

3 years ago

Pls help !!! pleaseee.

ladessa [460]

I guess B. That statement is grammatically incorrect.

8 0

2 years ago

Un productor agricola tiene que envasar huevos en cajas de 12, de 6 o de 30. Si sabemos que tiene un numero parecido a 1000 huev

musickatia [10]

Answer:

El productor tiene que envasar 960 huevos.

Step-by-step explanation:

Es necesario determinar el mínimo común múltiplo de 6, 12 y 30. En primer lugar, se determina cada número como productos de números primos:

$6 = 2\times 3$

$12 = 2^{2}\times 3$

$30 = 2\times 3\times 5$

El mínimo común múltiplo es:

$M.C.M. = 2^{2}\times 3\times 5$

$M.C.M. = 60$

El número total de huevos próximo a 1000 unidades es un múltiplo del mínimo común múltiplo:

$n = 60\times 16$

$n = 960$

El productor tiene que envasar 960 huevos.

5 0

3 years ago

Estimate the product of 26.4×2.7​

Estimate the product of 26.4×2.7