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kolezko [41]
3 years ago
15

A function is shown in the table below. What equation represents this function?

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
3 0

Answer:

y=-30+6+6 I hope it helps

have a good night

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The area of a sector of a circle is given by the equation uppercase A = StartFraction pi r squared uppercase S Over 360 EndFract
dlinn [17]

A circle is a curve sketched out by a point moving in a plane. The equation that Mia will write is S = (360 × A)/(πR²).

<h3>What is a circle?</h3>

A circle is a curve sketched out by a point moving in a plane so that its distance from a given point is constant; alternatively, it is the shape formed by all points in a plane that are at a set distance from a given point, the centre.

Given the area of the sector of a circle is given by,

A = (πR²×S)/360°

Now, If Mia solved this equation for S, then the equation that she will write is,

S = (360 × A)/(πR²)

Hence, the equation that Mia will write is S = (360 × A)/(πR²).

Learn more about Circle:

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2 years ago
Bell thinks there are four more tens in 45 than in 15. Is Bella correct? Explain your answer.
Ad libitum [116K]

Answer:no there are 3 more tens because 10 + 40 =50

Step-by-step explanation:

6 0
4 years ago
Here take my final 16 pts I need help with this Bella has one quiz left to take. On the first 5 quizzes, she received a 74%, 92%
lukranit [14]

Answer:

95

Step-by-step explanation:

Required Average

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80

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Average

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76

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84

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65

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320

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225

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320

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3 years ago
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3 years ago
Write an equation in standard form for the line, where the points (-2, -1) and (0, 4) are on the line
DedPeter [7]

Answer:

An equation in standard form for the line is:

\frac{5}{2}x-y=-4

Step-by-step explanation:

Given the points

  • (-2, -1) and (0, 4)

The slope between two points

\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-2,\:-1\right),\:\left(x_2,\:y_2\right)=\left(0,\:4\right)

m=\frac{4-\left(-1\right)}{0-\left(-2\right)}

m=\frac{5}{2}

Writing the equation in point-slope form

As the point-slope form of the line equation is defined by

y-y_1=m\left(x-x_1\right)

Putting the point (-2, -1) and the slope m=1 in the line equation

y-\left(-1\right)=\frac{5}{2}\left(x-\left(-2\right)\right)

y+1=\frac{5}{2}\left(x+2\right)

y=\frac{5}{2}x+4

Writing the equation in the standard form form

As we know that the equation in the standard form is

Ax+By=C

where x and y are variables and A, B and C are constants

so

y=\frac{5}{2}x+4

\frac{5}{2}x-y=-4

Therefore, an equation in standard form for the line is:

\frac{5}{2}x-y=-4

7 0
3 years ago
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