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3 years ago

Negative one-fifth of a number, increased by 3, is at most 1.

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

4 0

12 + 8 *89 is the answer

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Help me please i will really appreciate it

max2010maxim [7]

Answer:

2.H

Step-by-step explanation:

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3 years ago

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a park is rectangular with a length of 2/3 miles in the area of the park is 3/9 square miles what is it what is the width

Helen [10]

Answer:

The width w of the rectangular park = 1/2

Step-by-step explanation:

Given

The length of the rectangular park l = 2/3 miles

The area of the park A = 3/9 square miles

To determine

The width of the rectangular park w = ?

Using the formula of the Area of the rectangle

$A\:=\:wl$

$w\:=\:\frac{A}{l}$

$=\frac{\frac{3}{9}}{\frac{2}{3}}$

$=\frac{3\cdot \:3}{9\cdot \:2}$ ∵ Fraction rule: $\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a\cdot \:d}{b\cdot \:c}$

$=\frac{9}{18}$

$=\frac{1}{2}$

Therefore, the width w of the rectangular park = 1/2

6 0

3 years ago

Joey rode his bike 20 miles at a speed of 8 mph. How long did it take him?

Vlad1618 [11]

B) 2.5 hours , because 8 mph is 1 hour and the another 8mph is 1 hour 8+8mph =16mph 1+1hr=2hr half of 8 is 4mph is .5hr so therefore 8+8+4=20mph 1+1+ 30mins= 2.5hr

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3 years ago

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You are in charge of erecting a radio telescope on a newly discovered planet. To minimize interference, you want to place it whe

strojnjashka [21]

Answer:

Step-by-step explanation:

$\text{The equation of the surface of the sphere whose radius is 6 can be represented as:}$

$x^2+y^2+z^2 = 36}$

$So , g(x,y,z) = x^2 + y^2 + z^2 - 36$

$\text{To minimize the function :} \\ \\ M(x,y,z0 = 6x - y^2 +xz + 60$

$\text{by applying lagrange multipliers }$

$\bigtriangledown M (x,y,z) = \lambda \bigtriangledown g(x,y,z)$

$\langle 6+zz,-2y,x \rangle = \lambda \langle 2x,2y,2z \rangle$

$6+z = 2\lambda x$

$-2y = 2 \lambda y$

$\text{from the second equation ;} (\lambda +1)y = 0, \text{so , it is either y =0 or }\lambda = -1$

$Suppose \ \lambda = -1 ; \text{other equation becomes x = -2z and 6+z = -2x}$

$\text{such that; 6+z =4z or z = 2}$

$\text{it implies that: x= -4 and }y = \pm \sqrt{36 - 4-16} = \pm 4$

$\text{Here; there exist two possible points}$

$\text{(-4,-4,2) and (-4,4,2)}$

$\text{In the scenario here y=0,} \lambda \text{ is unknown, then we remove it}$

$x = 2 \lambda z \\ \\ 6+z = 2 \lambda x \\ \\ 6+z = 4 \lambda ^2z \\ \\ 6 = (4 \lambda ^2 -1) z ---(1)$

$z = \dfrac{6}{4 \lambda ^2 -1}$

$x = \dfrac{12 \lambda }{4 \lambda ^2 -1 }$

$\text{recall that; it i possible to divide }4 \lambda ^2 -1 \text{since (1) shows that it cannot be equal to zero.} \\ \\ \text{hence, puttinf this into constraint, whereby y =0, Then:}$