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lorasvet [3.4K]
2 years ago
13

Negative one-fifth of a number, increased by 3, is at most 1.

Mathematics
1 answer:
Morgarella [4.7K]2 years ago
4 0
12 + 8 *89 is the answer
You might be interested in
7 in.
fgiga [73]
258 cubic inches

Since the boxes are kind of on their own—>
First box: 7*2*12 = 168
Second box: 5*2*9=90
168+90 = 258
6 0
3 years ago
I am trying to figure this question: <br><br> 1 + tan^2A = Sec^2A
chubhunter [2.5K]

Answer:

see explanation

Step-by-step explanation:

Using the Pythagorean identity

cos²A + sin²A = 1 ( divide terms by cos²A )

\frac{cos^2A}{cos^2A} + \frac{sin^2A}{cos^2A} = \frac{1}{cos^2A} , that is

1 + tan²A = sec²A ← as required

3 0
3 years ago
Find the limit. (If an answer does not exist, enter DNE.) lim Δx→0 (x + Δx)2 − 3(x + Δx) + 2 − (x2 − 3x + 2) Δx
yawa3891 [41]

\displaystyle\lim_{\Delta x\to0}\frac{(x+\Delta x)^2-3(x+\Delta x)+2-(x^2-3x+2)}{\Delta x}

Expand the numerator as

x^2+2x\Delta x+(\Delta x)^2-3x-3\Delta x+2-x^2+3x-2=(2x-3)\Delta x+(\Delta x)^2

Then in the limit,

\displaystyle\lim_{\Delta x\to0}\frac{(2x-3)\Delta x+(\Delta x)^2}{\Delta x}=\lim_{\Delta x\to0}(2x-3+\Delta x)=\boxed{2x-3}

3 0
3 years ago
Coronao Coronao Coronao now now​
kari74 [83]
Need choices please ok
7 0
3 years ago
Find the errors and correct the following mathematical sentences.​
Varvara68 [4.7K]

Answer:

This is your answer ☺️☺️☺️

3 0
3 years ago
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