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Helen [10]
3 years ago
15

30 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! You have discovered another alien. Find the correct rescue path

before answering this question. Which statements are true about the equation of the line used to save this alien? The y-intercept is not visible on the graph. The slope does not exist for this line. The y-intercept is positive. The line crosses the x-axis at –3.
Mathematics
2 answers:
navik [9.2K]3 years ago
8 0

Answer:

A and D

Step-by-step explanation:

i did it on edge

elena-14-01-66 [18.8K]3 years ago
3 0

Answer:

Answer: B. Y= 0x + 0

Step-by-step explanation: It's a straight line to the alienbecause it's straight down the x-axis

Hope this helped!

Step-by-step explanation:

Answer: B. Y= 0x + 0

Step-by-step explanation: It's a straight line to the alienbecause it's straight down the x-axis

Hope this helped!

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Natali5045456 [20]
X + 3y -4 =0 or x=4 I think that’s the answer
4 0
2 years ago
Megan has practiced the piano for 7.5 hours over the course of this week. She practices on Tuesdays, Thursdays, and Saturdays. H
gulaghasi [49]

Answer:

150

Step-by-step explanation:

you have three days and 7.5 so decide 7.5 by 3 it equals 2.5 which in minutes is 150

7 0
3 years ago
A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a
zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}

Hence the answer is 0.1157

(ii) None is defective becomes

\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}

hence the answer is 0.4823

(iii) All are defective

\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}

(iv) At least one is defective

This is 1 - probability that none is defective

\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}

Hence the answer is 0.5177

3 0
10 months ago
PLEASE HELP ONE QUESTION THATS IT
dybincka [34]

Answer:

-3,2   -2,4  1,-1

Step-by-step explanation:

3 0
2 years ago
Use the identity x^3+y^3+z^3−3xyz=(x+y+z)(x^2+y^2+z^2−xy−yz−zx) to determine the value of the sum of three integers given:
RoseWind [281]

Inserting all the given information into the identity, we have

684-3(210)=(x+y+z)(110-107)\implies x+y+z=18

4 0
3 years ago
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