Guys pls HELP ME PLS I WOLL GIVE BRAINLIEST PLS

liq [111]

:V
the action or process of fertilizing an egg, female animal, or plant, involving the fusion of male and female gametes to form a zygote.

Hope this helps

5 0

3 years ago

When 542 mL of O2 gas at 30°C and 1.04 atm

Anastasy [175]

I hope this help you

5 0

3 years ago

Calcium carbonate breaks down into calcium oxide and liberates carbon dioxide. The whole reaction is driven by heat. What type o

fredd [130]

Answer: Thermal decomposition

Explanation:

Decomposition is a type of chemical reaction in which one reactant forms two or more than two products.

Decomposition reactions require breaking of bonds which require energy and thus all of the decomposition reactions are endothermic reactions. They require energy in the form of heat, electricity or sunlight and thus called as thermal, electrolytic and photolytic decomposition respectively.

The decomposition reaction for calcium carbonate breaks down into calcium oxide and liberates carbon dioxide is :

$CaCO_3\rightarrow CaO+CO_2$

5 0

3 years ago

Balance the equation _C2H6 + _H2O = _CO2 + _H2O

irinina [24]

Answer:

1, 4, 2 & 7 respectively

Explanation:

6 0

4 years ago

A chemist fills a reaction vessel with 3.82 atm methanol (CH,OH) gas, 7.56 am oxygen (O2) gas, 5.29 atm carbon dioxide (CO2) gas

alisha [4.7K]

<u>Answer:</u> The Gibbs free energy of the given reaction is $1.379\times 10^3kJ$

<u>Explanation:</u>

The equation used to calculate Gibbs free energy change is of a reaction is:

$\Delta G^o_{rxn}=\sum [n\times \Delta G^o_f_{(product)}]-\sum [n\times \Delta G^o_f_{(reactant)}]$

For the given chemical reaction:

$2CH_3OH(g)+3O_2(g)\rightarrow 2CO_2(g)+4H_2O(g)$

The equation for the Gibbs free energy change of the above reaction is:

$\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(CO_2(g))})+(4\times \Delta G^o_f_{(H_2O(g))})]-[(2\times \Delta G^o_f_{(CH_3OH(g))})+(3\times \Delta G^o_f_{(O_2(g))})]$

We are given:

$\Delta G^o_f_{(H_2O(g))}=-228.57kJ/mol\\\Delta G^o_f_{(CO_2(g))}=-394.36kJ/mol\\\Delta G^o_f_{(CH_3OH(g))}=-161.96kJ/mol\\\Delta G^o_f_{(O_2(g))}=0kJ/mol$

Putting values in above equation, we get:

$\Delta G^o_{rxn}=[(2\times (-394.36))+(4\times (-228.57))]-[(2\times (-161.96))+(3\times (0))]\\\\\Delta G^o_{rxn}=-1379.08kJ/mol$

The equation used to Gibbs free energy of the reaction follows:

$\Delta G=\Delta G^o+RT\ln Q_{p}$

where,

$\Delta G$ = free energy of the reaction

$\Delta G^o$ = standard Gibbs free energy = -1379.08 kJ/mol = -1379080 J/mol (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/K mol

T = Temperature = $25^oC=[273+25]K=298K$

$Q_{p}$ = Ratio of concentration of products and reactants = $\frac{(p_{CO_2})^2(p_{H_2O})^4}{(p_{CH_3OH})^2(p_{O_2})^3}$

$p_{CO_2}=5.29atm\\p_{H_2O}=3.89atm\\p_{CH_3OH}=3.82atm\\p_{O_2}=7.56atm$

Putting values in above expression, we get:

$\Delta G=-1379080J/mol+(8.314J/K.mol\times 298K\times \ln (\frac{(5.29)^2\times (3.89)^4}{(3.82)^2\times (7.56)^3}))\\\\\Delta G=-1379039J=1379.039kJ=1.379\times 10^3kJ$

Hence, the Gibbs free energy of the given reaction is $1.379\times 10^3kJ$

5 0

4 years ago