Answer:
1. Based on the given question, 138.03 grams of NO₂ is reacting completely with 18.02 grams of H2O. However, in case when 359 grams of NO₂ is used then the grams of water consumed in the reaction will be,
= 359 × 18.02 / 138.03 = 46.87 grams of water.
2. As mentioned in the given case 138.03 grams of NO₂ generates 126.04 grams of HNO₃. Therefore, 359 grams of NO₂ will produce,
= 359 × 126.04 / 138.03
= 327.81 grams of HNO₃.
3. Based on the given question, 138.04 grams of NO₂ is generating 30.01 grams of NO. Therefore, 359 grams of NO₂ will generate,
= 359 × 30.01 / 138.04
= 78.04 grams of NO.
Answer: I already gave u the aNswer
Explanation:0 ok bye
bye .................................
Answer:
a. -58 millivolts
Explanation:
The given Nernst equation is:
![E_{ion} = 58 millivolts /z \Big[ log_{10} \Big( \dfrac{[ion]_{out}}{[ion]_{in}}\Big) \Big]}](https://tex.z-dn.net/?f=E_%7Bion%7D%20%3D%2058%20millivolts%20%2Fz%20%5CBig%5B%20log_%7B10%7D%20%5CBig%28%20%5Cdfrac%7B%5Bion%5D_%7Bout%7D%7D%7B%5Bion%5D_%7Bin%7D%7D%5CBig%29%20%5CBig%5D%7D)
The equilibrium potential given by the Nernst equation can be determined by using the formula:
![E_{Cl^-} = \dfrac{2.303*R*T}{ZF} \times log \dfrac{[Cl^-]_{out}} {[Cl^-]_{in}}](https://tex.z-dn.net/?f=E_%7BCl%5E-%7D%20%3D%20%5Cdfrac%7B2.303%2AR%2AT%7D%7BZF%7D%20%5Ctimes%20log%20%5Cdfrac%7B%5BCl%5E-%5D_%7Bout%7D%7D%20%7B%5BCl%5E-%5D_%7Bin%7D%7D)
where:
gas constant(R) = 8.314 J/K/mol
Temperature (T) = (20+273)K
= 298K
Faraday constant F = 96485 C/mol
Number of electron on Cl = -1




Answer:
your question is totally wrong. there is no cl2 in reactants.
Answer is 1.41 x 10 with the exponent of 24, atoms
Explanation : Look at the picture i attached.