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Maksim231197 [3]

3 years ago

9

The formula C2H4 can be described as

2 answers:

Mila [183]3 years ago

8 0

C2H4 is Ethylene. Ethylene is a simple hydrocarbon alkaline.

Elden [556K]3 years ago

4 0

It's describe as Ethylene

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How many molecules are there in 2.30 grams of NH3

mixer [17]

<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We calculate as follows:

2.30 g NH3 (1 mol / 17.03 g ) (</span>6.022 x 10^23 molecules / 1 mol ) = 8.13x10^22 molecules

7 0

3 years ago

The light traveled from _____________________ to __________________. (What transparent materials?)

sergiy2304 [10]

Explanation:

High density medium to low density medium.

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2 years ago

What causes the shielding effect to remain constant across a period?

Ivanshal [37]

Electrons are added to the same principal energy level.

5 0

3 years ago

Nitrogen and hydrogen combine to form ammonia in the Haber process. Calculate (in kJ) the standard enthalpy change ΔH° for the r

PolarNik [594]

Answer: -105 kJ

Explanation:-

The balanced chemical reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

The expression for enthalpy change is,

$\Delta H=\sum [n\times B.E(reactant)]-\sum [n\times B.E(product)]$

$\Delta H=[(n_{N_2}\times B.E_{N_2})+(n_{H_2}\times B.E_{H_2}) ]-[(n_{NH_3}\times B.E_{NH_3})]$

$\Delta H=[(n_{N_2}\times B.E_{N\equiv N})+(n_{H_2}\times B.E_{H-H}) ]-[(n_{NH_3}\times 3\times B.E_{N-H})]$

where,

n = number of moles

Now put all the given values in this expression, we get

$\Delta H=[(1\times 945)+(3\times 432)]-[(2\times 3\times 391)]$

$Delta H=-105kJ$

Therefore, the enthalpy change for this reaction is, -105 kJ

8 0

3 years ago

Air has a mass of 1.2g and a volume of 4,555ml. What is the density

coldgirl [10]

Answer:

<h2>Density = 0.00026 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3> $Density(\rho) = \frac{mass}{volume}$ </h3>

From the question

mass of air = 1.2 g

volume = 4,555 mL

Substitute the values into the above formula and solve for the density

That's

<h3> $Density = \frac{1.2}{4555}$ </h3>

= 0.0002634

We have the final answer as

<h3>Density = 0.00026 g/mL</h3>

Hope this helps you

3 0

3 years ago