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Anna71 [15]
3 years ago
12

The polled (hornless) condition (P) is dominant over horned (p). A certain polled bull is crossed to 3 cows.

Biology
1 answer:
Rashid [163]3 years ago
3 0

Answer and Explanation:

Due to technical problems, you will find the complete answer and explanation in the attached files

Download pdf
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If two organisms reproduce asexually, then they will be able to produce offspring _______ two organisms that reproduce sexually.
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Lucy is thinking of a 5 digit number
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23,7_4

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The forward and reverse PCR primers used for the amplification of a VNTR locus on chromosome number 4 are 20 bases and 21 bases
zimovet [89]

The repeats which occur together on a chromosome are referred to as VNTR. The length of each repeat is 60bp.

The first primer is 20bp and is 53 bp away from 1st repeat. Therefore, the total length of sequence amplified by the first primer till 1st repeat = 20+53 = 73bp. Beyond this point 6 repeats on 60 bp are present, hence, the length becomes = 73 + (60X6) = 433bp.

Now the reverse primer which is 21bp in length is located 28bp from the repeat on its side. Reverse primer comes from the opposite direction, so it must be present after the 6 repeats.

The total length of the amplified region = 433 + 28 + 21 = 482 bp.

5 0
3 years ago
Help please !! I really don’t understand this much☹️
morpeh [17]
Ok, so I wrote these out just to make it a little bit easier for you to understand what I am about to explain.

So for the first one you have two different traits that can be inherited- having freckles or having no freckles, F and f respectively. The dominant trait (or having freckles) is shown by the capital F, and is almost always expressed over the recessive trait, or the lowercase f. So, for example, if you have a genotype of Ff, the trait having freckles will show up instead of not having freckles. The only way that you could have the trait of no freckles show up is if there are two recessive alleles for having no freckles, or ff. In this case, you have two parents who are both heterozygous for the trait of having freckles, so in other words the mother has Ff and the father has Ff. Each parent passes down one allele to the offspring, so since you are breeding Ff and Ff, you should result in having the possible genotypes of FF, Ff, Ff, and ff. This means that there is a 25% chance that the offspring will be homozygous for having freckles, a 50% chance that the offspring will be heterozygous for having freckles and a 25% chance that they would be homozygous for having no freckles, or a 1:2:1 ratio.

Incomplete dominance is a little bit different that just a normal monohybrid cross. Instead of just the dominant gene showing up in a heterozygous genotype, both traits show up. So like the question says, if a homozygous red flower plant was crossed with a homozygous white flower plant, their offspring would not just be white or red, they would be pink because it is a mixture of white and red. So then if you crossed the heterozygous, or Rr plants, the result would be a 25% chance of getting a homozygous RR red plant, a 50% chance of getting a pink Rr plant, and a 25% chance of getting a white rr plant, or another 1:2:1 ratio.

Sorry for the wordy answer, but hopefully this helps you understand this a little better :)

4 0
3 years ago
Which of the following is an example of phagocytosis? : A cell takes in large amounts of water. A cell in the thyroid gland secr
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An amoeba wraps its membrane around a small unicellular organism to eat it.

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