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Georgia [21]
3 years ago
5

Solve |x+2|=10 Please help

Mathematics
2 answers:
Anvisha [2.4K]3 years ago
7 0

x = 8, --- 12

I hope this helped :))))))))))))))))))

valentinak56 [21]3 years ago
5 0

Answer:

x = 8, - 12

i hope this is what you were looking for

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lin has 8 green apples and 2 red apples .if he slices the green apples in eighths ,how many apple slices will he have ?
lutik1710 [3]
64 because each apple is sliced into 8ths and there are 8 apples so 8x8=64
3 0
3 years ago
A number is multiplied by -58. the product is -0.4. what is the value of n?
quester [9]

Answer:

n = 145

Step-by-step explanation:

-58 ÷ -0.4 = 145

n = 145

5 0
3 years ago
Find the area of the shaped region
Ganezh [65]

Answer: B

Step-by-step explanation:

A = 0/360 ×π×r^2

=135/360×π×11×11

=142.55 yd^2

5 0
3 years ago
What is the probability that a random person who tests positive for a certain blood disease actually has the disease, if we know
xeze [42]

Answer:

Step-by-step explanation:

Hello!

Any medical test used to detect certain sicknesses have several probabilities associated with their results.

Positive (test is +) ⇒ P(+)

True positive (test is + and the patient is sick) ⇒ P(+ ∩ S)

False-positive (test is + but the patient is healthy) ⇒P(+ ∩ H)

Negative (test is -) ⇒ P(-)

True negative (test is - and the patient is healthy) ⇒ P(- ∩ H)

False-negative (test is - but the patient is sick) ⇒ P(- ∩ S)

The sensibility of the test is defined as the capacity of the test to detect the sickness in sick patients (true  positive rate).

⇒ P(+/S) =<u> P(+ ∩ S)  </u>

                    P(S)

The specificity of the test is the capacity of the test to have a negative result when the patients are truly  healthy (true negative rate)

⇒ P(-/H) =<u> P(- ∩ H)  </u>

                   P(H)

For this particular blood disease the following probabilities are known:

1% of the population has the disease: P(S)= 0.01

95% of those who are sick, test positive for it: P(+/S)= 0.95 (sensibility of the test)

2% of those who don't have the disease, test positive for it: P(+/H)= 0.02

The probability of a person having the blood sickness given that the test was positive is:

P(S/+)= <u> P(+ ∩ S)  </u>

                P(+)

The first step you need to calculate the intersection between both events + and S, for that you will use the information about the sickness prevalence in the population and the sensibility of the test:

P(+/S) =<u> P(+ ∩ S) </u>

                 P(S)

P(+/S)* P(S)  = P(+ ∩ S)  

P(+ ∩ S) = 0.95*0.01= 0.0095

The second step is to calculate the probability of the test being positive:

P(+)=  P(+ ∩ S) +  P(+ ∩ H)

Now we know that 1% of the population has the blood sickness, wich means that 99% of the population doesn't have it, symbolically: P(H)= 0.99

Then you can clear the value of P(+ ∩ H):

P(+/H) =<u> P(+ ∩ H) </u>

                 P(H)

P(+/H)*P(H)  = P(+ ∩ H)

P(+ ∩ H) = 0.02*0.99= 0.0198

Next you can calculate P(+):

P(+)=  P(+ ∩ S) +  P(+ ∩ H)= 0.0095 + 0.0198= 0.0293

Now you can calculate the asked probability:

P(S/+)= <u> P(+ ∩ S)  </u> =<u> 0.0095 </u>= 0.32

                P(+)        0.0293

I hope it helps!

                 

                 

6 0
3 years ago
The football referee calls a penalty of 5 yards against a team in addition to a loss 3 yards. If another referee calls an additi
nignag [31]

Answer: 18 yards.

Step-by-step explanation: 5 + 3 + 10 = 18 Brainliest please?

8 0
3 years ago
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