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avanturin [10]
3 years ago
12

Solve for. x -2x – 3 = 7

Mathematics
1 answer:
Maurinko [17]3 years ago
3 0

Answer:

x = -5

Step-by-step explanation:

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A card is drawn from a pack of 52 cards. Find the probability of drawing an ace given that it is diamond.4/521/132/134/13
ICE Princess25 [194]

Solution:

The probability of an event is expressed as

P(event)=\frac{number\text{ of desired outcome}}{number\text{ of possible outcome}}

In a pack of 52 cards, we have

\begin{gathered} number\text{ of diamonds=13} \\ number\text{ of ace= 1} \end{gathered}

Thus, we have the probability to be evaluated as

P(ace)=\frac{1}{13}

8 0
1 year ago
Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
2 years ago
Select all the angle measurements that are correct
valina [46]

Answer:

a = 132

b = 132

d = 29

e = 29

f = 151

g = 24

h = 24

6 0
3 years ago
Please do all four, thanks :) <br><br> I'm feeling generous today *40 points*
MrMuchimi

Step-by-step explanation:

A. x^2-9x+18

B. x^2-8x+16

C. 2x^2-5x-12

D. 12x^2-31x+7

8 0
3 years ago
Read 2 more answers
Write the expression (−2)·(−2)·7·7·7·7·7 using exponents.
NeTakaya

Answer:(-2)^{2}*7^{5}

Step-by-step explanation:

You have to group all of the same one's together and however many there is, you add that number as the exponent.

There were 2 "(-2)" so that became (-2)^{2}, and there were 5 "7" so that became 7^{5}. You keep the symbol and put it together which became (-2)^{2}*7^{5}

5 0
2 years ago
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