The length of the rectangle is 20 inches, and the width of the rectangle is 4 inches if the table runner has an area of 80 square inches. The length and width of the table runner are whole numbers. The length is 5 times greater than the width.
<h3>What is the area of the rectangle?</h3>
It is defined as the space occupied by the rectangle which is planner 2-dimensional geometry.
The formula for finding the area of a rectangle is given by:
Area of rectangle = length × width
The area of the table runner = 80 square inches
Let's assume the length of the rectangle is L and the width is W
Then L = 5×W ...(1)
L×W = 80 ...(2)
Put the value of L in the equation (2)
5W(W) = 80
5W² = 80
W² = 16
W = ±4
Width cannot be negative.
W = 4 inches putting this value in the equation (1)
L = 5(4) = 20 inches
Thus, the length of the rectangle is 20 inches, and the width of the rectangle is 4 inches if the table runner has an area of 80 square inches. The length and width of the table runner are whole numbers. The length is 5 times greater than the width.
Learn more about the area here:
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Answer:

Step-by-step explanation:
A polynomial is given to us and we need to make the polynomial by its degree . Here the given polynomial is 3x² + 5x -3 .

So here we can see that the highest power of the variable in the given polynomial is 2 . So the polynomial is a quadratic polynomial .
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When we equate this quadratic polynomial with 0 , it becomes a quadratic equation.
That is ,
This is done in order to find the zeroes of the polynomial. The zeroes of the polynomial are the values for which the polynomial becomes 0 .
Answer:
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Step-by-step explanation:
From the question we are told that:
Price of 20TVs per week
Marginal price-demand function 
Generally the The Marginal price function is mathematically given by
Therefore the equation when the demand is 20 TVs per week at $150 per TV

Giving

Therefore the Price when the demand is 100 TVs per week


He would lose 350,000 dollars or -350,000.
Check the picture below, that's just an example of a parabola opening upwards.
so the cost equation C(b), which is a quadratic with a positive leading term's coefficient, has the graph of a parabola like the one in the picture, so the cost goes down and down and down, reaches the vertex or namely the minimum, and then goes back up.
bearing in mind that the quantity will be on the x-axis and the cost amount is over the y-axis, what are the coordinates of the vertex of this parabola? namely, at what cost for how many bats?

![\bf \left( -\cfrac{-7.2}{2(0.06)}~~,~~390-\cfrac{(-7.2)^2}{4(0.06)} \right)\implies (60~~,~~390-216) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (\stackrel{\textit{number of bats}}{60}~~,~~\stackrel{\textit{total cost}}{174})~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cleft%28%20-%5Ccfrac%7B-7.2%7D%7B2%280.06%29%7D~~%2C~~390-%5Ccfrac%7B%28-7.2%29%5E2%7D%7B4%280.06%29%7D%20%5Cright%29%5Cimplies%20%2860~~%2C~~390-216%29%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%28%5Cstackrel%7B%5Ctextit%7Bnumber%20of%20bats%7D%7D%7B60%7D~~%2C~~%5Cstackrel%7B%5Ctextit%7Btotal%20cost%7D%7D%7B174%7D%29~%5Chfill)