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sp2606 [1]
3 years ago
13

Is this correct? pLeAsE lOoK aT tHe ImAgE bElOw!!! Have a great day!

Mathematics
2 answers:
vfiekz [6]3 years ago
8 0

Answer:

false

true

false

Step-by-step explanation:

||=postive answer so it's greater than 0

Scrat [10]3 years ago
3 0
Answer
False true false
Explanation plz give brainliest
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Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in
Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

It is provided that:

<em>n</em> = 20

<em>s</em> = 3.9

Confidence level = 95%

⇒ <em>α</em> = 0.05

Compute the critical values of Chi-square:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0
3 years ago
There are 120 boys in Morris middle school. What is the total number
AnnZ [28]

Answer:

121

Step-by-step explanation:

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8 0
3 years ago
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45(15x+20)−7x=56(12x−24)+6 Enter your answer in the box. 
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X=1119/2 hope this helps :)
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3 years ago
Find the Surface Area<br> and Volume of the<br> following:<br> 25 points with work!!
adoni [48]

Step-by-step explanation:

The surface area volume = l×b

or, 14×10 cm = 140 ans

8 0
3 years ago
At one​ store, Julia saved ​$10 with a coupon for 40​% off her total purchase. At another​ store, the ​$29 she spent on books is
barxatty [35]
Let "a" and "b" represent the values of the first and second purchases, respectively.
  0.40*(original price of "a") = $10
  (original price of "a") = $10/0.40 = $25.00 . . . . divide by 0.40 and evaluate
  a = (original price of "a") - $10 . . . . . . Julia paid the price after the discount
  a = $25.00 -10.00 = $15.00

At the other store,
  $29 = 0.58b
  $29/0.58 = b = $50 . . . . . . . divide by the coefficient of b and evaluate

Then Julia's total spending is
  a + b = $15.00 +50.00 = $65.00

Julia spent $65 in all at the two stores.
6 0
3 years ago
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