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3 years ago

Which group of numbers is listed from least to greatest?

Mathematics

2 answers:

Nataliya [291]3 years ago

8 0

Answer:

1.) -6, |-3|, -3, 6, |-9| __ |-9|, -6, -3,|-3|, 6

2.) -8, |-5|, -4, |3|, 6 __ -8, |-5|, -4, |3|, 6

3.) -4, |-2|, |3|, 5, |-7| __ |-7|, -4, |-2|, |3|, 5

4.) |-6|, -4, |-2|, -1, 0 __ |-6|, -4, |-2|, -1, 0

Step-by-step explanation:

2.) -8, |-5|, -4, |3|, 6 __ -8, |-5|, -4, |3|, 6

4.) |-6|, -4, |-2|, -1, 0 __ |-6|, -4, |-2|, -1, 0

Both are listed from least to greatest

ycow [4]3 years ago

3 0

The third option
An absolute value symbol means that whatever is in between automatically turns into a positive number
You would get...
-4,2,3,5,7 which is an order sequence from least to greatest

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Point B is at (3,1).

Alik [6]

Answer:

A(1,−1) and C(5,3)

Step-by-step explanation:

6 0

3 years ago

Solve for x. Round all answers to the nearest tenth. 9 X 12

maria [59]

Step-by-step explanation:

x=54

use pyth then the other line = 15

then 15÷90 = 9÷x

then x = 54

8 0

3 years ago

Read 2 more answers

Help help I don’t really get this???

insens350 [35]

Answer:

Question 4: $y=\displaystyle -\frac{4}{5}x$

Question 5: $y=-5x-3$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope of the line and b is the y-intercept (the y-coordinate of the point where the line crosses the y-axis).

Question 4

1) Determine the slope (m)

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$ where two points that pass through the line are $(x_1,y_1)$ and $(x_2,y_2)$

In the graph, two easy-to-identify points on the line are (-5,4) and (5,-4). Plug these into the equation:

$\displaystyle m=\frac{-4-4}{5-(-5)}\\\\\displaystyle m=\frac{-4-4}{5+5}\\\\\displaystyle m=\frac{-8}{10}\\\\\displaystyle m=-\frac{4}{5}$

Therefore, the slope of the line is $\displaystyle -\frac{4}{5}$ . Plug this into $y=mx+b$ as the slope (m):

$y=\displaystyle -\frac{4}{5}x+b$

2) Determine the y-intercept (b)

On the graph, we can see that the line crosses the y-axis when y is 0. Therefore, the y-intercept (b) is 0. Plug this into $y=\displaystyle -\frac{4}{5}x+b$ :

$y=\displaystyle -\frac{4}{5}x+0\\\\y=\displaystyle -\frac{4}{5}x$

Question 5

1) Determine the slope (m)

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Two easy-to-identify points are (-1,2) and (0,-3). Plug these into the equation:

$\displaystyle m=\frac{-3-2}{0-(-1)}\\\\\displaystyle m=\frac{-3-2}{0+1}\\\\\displaystyle m=\frac{-5}{1}\\\\m=-5$

Therefore, the slope is -5. Plug this into $y=mx+b$ :

$y=-5x+b$

2) Determine the y-intercept (b)

On the graph, we can see that the line crosses the y-axis at the point (0,-3). The y-coordinate of this point is -3. Therefore, the y-intercept (b) is -3. Plug this into $y=-5x+b$ :

$y=-5x+(-3)\\y=-5x-3$

I hope this helps!

8 0

2 years ago

I WILL GIVE BRAINILY... I need the full equation ASAP THANK YOU!!

photoshop1234 [79]

Answer:

$y=\frac{9}{10} x-\frac{7}{5}$

Step-by-step explanation:

points on the line:- (-4,-5)&(6,4)

slope= 4+5/6+4= 9/10

y-4=9/10(x-6)

y=9x/10-54/10+4

y=9/10 x-7/5

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┍━━━━ ⋆⋅☆⋅⋆ ━━━━┑

hope it helps..

have a great day!!

┕━━━━ ⋆⋅☆⋅⋆ ━━━━┙

6 0

3 years ago

Need that help.......plz

Anika [276]

For Question Number one
(2+10)²+4=148

Question Number two:
(6+5)×(8-6)=22

5 0

3 years ago