Question

please help me please if some one answers my question next i will post 100 points free if some one answers this question please

Answer 1

Answer:

$(0,60) = = > the \: vertical \: displacement \: of \: the \: automobile (y-intercept) \\ (6,0) = = > the \: horizontal \: displacement \: of \: the \: automobile (x-intercept) \\ equation \\ y = mx + c \\note = > m = \frac{(0 - 60)}{(6 - 0)} \\ m = - 10 \\ consider \: point \: (6,0) \\ from \: y = mx + c \\ substitute \: for \: y \: and \: x \\ 0 = (m)(6) + c \\ 0 = ( - 10 \times 6) + c \\ 0 = - 60 + c \\ c = 60 \\ substitute \: for \: c \: in \: y = mx + c \\ y = - 10x +60 \\ 10y = - x + 6$

Answer 2

Answer:

Step-by-step explanation:

a) the points (0,60)  and (6.0) are the intercept points for the graph of the car slowing down ( accelerating in the opposite direction than it's traveling)

we already know the slope of the line b/c that the rate at which it's slowing .. -10 =m  which is the slope of the line .. down 10

use the point-slope formula  y-y1 = m(x-x1) and plug in either given point for (x1,y1)

b) y -60 = -10(x-0)

y= -10x+60

thats the slope-intercept form of the equation