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snow_tiger [21]
2 years ago
11

CaN SOmE One HELp MeH?

Mathematics
2 answers:
vredina [299]2 years ago
8 0

the area is 863

17 times 14 equals 238

25 times 25 equals 625

625 plus 238 equals 863

RUDIKE [14]2 years ago
5 0

Divide the shape into 2 different rectangles:

25 x 11 = 275

42 x 14 = 588

Total area = 275 + 588 = 863 square yards.

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HELP PLEASEEE I NEED HELP QUICK
madam [21]

Answer:

C) If the perfect square terms are A^2 and B^2 and other terms must be 2 AB and -2AB

Step-by-step explanation:

As,

(a^2+2ab+b^2)=(a+b)^2\\(a^2-2ab+b^2)=(a-b)^2

7 0
2 years ago
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A rectangle is four times as long as it is wide. If its length were diminished by 6 meters and its width were increased by 6 met
valkas [14]

Answer:

Length equals 16 and Width equals 4

Step-by-step explanation:

First let us create an equation. We can use L and W for length and width.

If the length is 4 times the width, then we end up with: L = 4W

It then says, " If its length were diminished by 6 meters and its width were increased by 6 meters, it would be a square."

Since a square has an equal length and width then we end up with:

L - 6 = W + 6

Knowing this we can just substitute the first equation into the second one leaving us with: 4W - 6 = W + 6

We then remove a W from both sides so that the right side is left with a 6, and add 6 to both sides to remove the -6 from the left one.

This leaves us with 3W = 12

W = 4, and if we put that into our first equation, L = 4W, then Length equals 16, and Width equals 4. We can check this by putting it into the 2nd equation. 16 - 6 = 4 + 6.

7 0
1 year ago
£110 is divided between Stephen, Bridget & Caroline so that Stephen gets twice as much as Bridget, and Bridget gets three ti
faltersainse [42]

Answer:

I have no clue I really don't have no clue but you 10 divided by 3 and then you could double it by 2 and then after that you could develop by 3 and then that's how much Stephen get

3 0
2 years ago
Consider the problem of distributing 10 distinct books among three different people with each person getting at least one book.
kakasveta [241]

The strategy used is not well, because it becomes very complex and very difficult to calculate the ways, it would play one by one, that is, despite making sense, the last part of the way to distribute the books how is it obtained? why would it be like this?

There is a much more effective way of solving the problem, and that is to divide it by cases.

Case 1:

Choose four books from the 10 available books and give them to the first student

Then choose three books from the remaining six books and give them to the second student.

Finally, give the remaining three books to the last student

Case 2:

Choose three books from the 10 available books and give them to the first student

Then choose four books from the remaining seven books and give them to the second student.

Finally, give the remaining three books to the last student

Case 3:

Choose three books from the 10 available books and give them to the first student

Then choose three books from the remaining seven books and give them to the second student.

Lastly, give the remaining four books to the last student

First it is to calculate the number number in each case by means of combinations, multiply the options per case and then add the final value in each case.

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3 years ago
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777dan777 [17]

Answer: down there :)

Step-by-step explanation:

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