(4 mol H2O) x (112 kJ / 3 mol H2O) = 149 kJ
<span>(14.5 g HCl) / (36.4611 g HCl/mol) x (112 kJ / 3 mol HCl) = 14.9 kJ </span>
<span>(475 kJ) / (181 kJ / 2 mol HgO) x (216.5894 g HgO/mol) = 1137 g HgO </span>
<span>(179 kJ) / (181 kJ / 1 mol O2) x (31.99886 g O2/mol) = 31.6 g O2 </span>
<span>(145 kJ) / (112 kJ / 3 mol Cl2) x (70.9064 g Cl2/mol) = 275 g Cl2 </span>
<span>(14.5 g S2Cl2) / (135.0360 g S2Cl2/mol) x (112 kJ / 1 mol S2Cl2) = 12.0 kJ </span>
<span>CaCO3 + 2 NH3 → CaCN2 + 3 H2O; ∆H = –90.0 kJ </span>
<span>(798 kJ) / (90.0 kJ / 2 mol HN3) x (17.03056 g NH3/mol) = 302 g NH3 </span>
<span>(19.7 g H2O) / (18.01532 g H2O/mol) x (90.0 kJ / 3 mol H2O) = 32.8 kJ</span>
The % yield of Hf is 91. 8%
calculation
% yield = actual mass/ theoretical mass x100
actual mass = 2.85 Kg
calculate the theoretical mass
by first write the equation for reaction
CaF2 +H2SO4 → 2HF + CaSO4
find the moles of CaF2 used
moles = mass/molar mass
mass = 6.05Kg = 6.05 x1000 =6050 Kg
molar mass of CaF2 = 40 + (19 x2) = 78 g/mol
moles= 6050/ 78 = 77.6 moles
by use of mole ratio between CaF2 to HF which is 1:2 the moles of HF is therefore = 77.6 x2 =155.2 moles of Hf
find the theoretical mass of HF = moles x molar mass ( 1 +19=20g/mol)
= 155.2 moles x 20 g/mol = 3104 grams = 3104 /1000 = 3.104 Kg
The % yield is therefore = 2.85 Kg/ 3.104 Kg x100 = 91.8%
If the potassium ions were represented by spheres, the smaller one is the ion and the bigger one is the (neutral) atom.
Generally, metallic atoms (such as potassium) readily form cations (positively-charged ions) by losing electrons in their outer shells. By losing these electrons, the atoms are expected to be smaller in size. However for nonmetals, they readily gain electrons to form anions (negatively-charged ions). By gaining these electrons in their outer orbital shells, the ions generally then becomes larger.
Answer:
La datación potasio-argón o 40K/40Ar es un método de datación radiométrica, surgido en la década de 1960, utilizado en geología y arqueología para datar rocas o cenizas volcánicas
Answer:
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Explanation:
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