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Marianna [84]
3 years ago
7

6. Which of the following could be a base in a water solution?

Chemistry
1 answer:
Elza [17]3 years ago
5 0

Answer:

h20

Explanation:

H2O is an acid and a base, and H20 is water.

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When you apply heat energy to a substance, where does the energy go? Think about the law of conservation of energy.
Softa [21]

Answer:

the heat energy is transformed to any kind of energy depending on what it's meant to be transformed to.

remember it cannot be destroyed so it's definitely transformed to some kinda energy

8 0
3 years ago
Consider the following two substances andtheir vapor pressures at 298 \rm K.Substance Vapor pressure (\rm mmHg) A 275 B 459Based
Dafna11 [192]

Explanation:

The pressure exerted by vapors or gas on the surface of a liquid is known as vapor pressure.

This means that weaker is the intermolecular forces present in a substance more easily it can form vapors. As a result, it will have high vapor pressure.

As substance B has high vapor pressure which means that it has weak intermolecular forces.

Also, stronger is the intermolecular forces present in a substance more will be its boiling point. Hence, more energy or temperature is required to break the bonds. Hence, substance A has higher boiling point and high heat of vaporization.

When surrounding pressure is less than or equal to its vapor pressure then substance B boils into the gas phase. Hence, substance B will be a gas at 300 mm Hg.

Therefore, we can conclude that characteristics of the two substances will be as follows.

(a) Substance B - has weaker intermoclcular

(b) Substance A - has a higher boiling point

(c) Substance B - is a gas at 300 mm Hg

(d) Substance A - has a higher heat of vaporization

8 0
3 years ago
Calculate the concentration of a solution formed by dissolving 5.6 g of potassium
gayaneshka [121]

The concentration of solution : 0.2 M

<h3> Further explanation </h3>

Given

5.6 g Potassium hydroxide(KOH)

500 ml of solution = 0.5 L

Required

The concentration

Solution

Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution

MW KOH = 39+16+1=56 g/mol

mol solute(KOH) :

= mass : MW KOH

= 5.6 : 56 g/mol

= 0.1

Molarity :

= 0.1 : 0.5

= 0.2 M

7 0
3 years ago
Which amino acid chain will be formed by the codons shown below? aag aga ugu?
notsponge [240]
The amino acid chain will be; Lysine-Arginine-Cysteine 
Amino acids are the building block of proteins, many amino acid molecules make up polypeptide chains which form proteins. Each amino acid is coded by a specific codon during the process of translation. A codon consists of three nucleotide bases. In this case AAG codes for amino acid Lysine, while AGA codes for Arginine and UGU codes for amino acid Cysteine.
3 0
3 years ago
A 8.00g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of
Ne4ueva [31]

Answer:

C3H6.

Explanation:

Data obtained from the question:

Mass of the compound = 8g

Mass of CO2 = 24.01g

Mass of H2O = 13.10g

Next, we shall determine the mass of C, H and O present in the compound. This is illustrated below:

Molar Mass of CO2 = 12 + (2x16) = 44g/mol

Molar Mass of H2O = (2x1) + 16 = 18g/mol

Mass of C in compound = Mass of C/Molar Mass of CO2 x 24.01

=> 12/44 x 24.01 = 6.5g

Mass of H in the compound = Mass of H/Molar Mass of H2O x 13.1

=> 2x1/18 x 13.1 = 1.5g

Mass of O in the compound = Mass of compound – (mass of C + Mass of H)

=> 8 – (6.5 + 1.5) = 0

Next, we shall determine the empirical formula of the compound. This is illustrated below:

C = 6.5g

H = 1.

Divide by their molar mass

C = 6.5/12 = 0.54

H = 1.4/1 = 1.

Divide by the smallest

C = 0.54/0.54 = 1

H = 1/0.54 = 2

Therefore, the empirical formula is CH2

Finally, we shall determine the molecular formula as follow:

The molecular formula of a compound is a multiple of the empirical formula.

Molecular formula = [CH2]n

[CH2]n = 44

[12 + (2x1)]n = 44

14n = 44

Divide both side by 14

n = 44/14

n = 3

Molecular formula = [CH2]n = [CH2]3 = C3H6

Therefore, the molecular formula of the compound is C3H6

4 0
3 years ago
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