Answer is: the % ionization of hypochlorous acid is 0.14.
Balanced chemical
reaction (dissociation) of an aqueous solution of hypochlorous acid:
HClO(aq) ⇄ H⁺(aq) + ClO⁻(aq).
Ka = [H⁺] · [ClO⁻] / [HClO].
[H⁺] is equilibrium concentration of hydrogen cations or protons.
[ClO⁻] is equilibrium concentration of hypochlorite anions.
[HClO]
is equilibrium concentration of hypochlorous acid.
Ka is the acid
dissociation constant.
Ka(HClO) = 3.0·10⁻⁸.
c(HClO) = 0.015 M.
Ka(HClO) = α² · c(HClO).
α = √(3.0·10⁻⁸ ÷ 0.015).
α = 0.0014 · 100% = 0.14%.
When it would be on a flat area with no slope. and no movement
Answer:
See explanation
Explanation:
The mechanism of this reaction including intermediates are shown in the image attached to this answer.
The reaction of HBr with 3-bromocyclohexene yields trans-1,2-dibromocyclohexane as the sole product because; the proton first attacks the 3-bromocyclohexene and a brominium ion is formed. This brominium ion is a cyclic intermediate as shown in the image attached.
Attack of a bromine ion afterwards must lead to the formation of trans-1,2-dibromocyclohexane as shown.