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s344n2d4d5 [400]
1 year ago
10

How many moles of methane are produced when 4.53 mol co2 reacts

Chemistry
2 answers:
ArbitrLikvidat [17]1 year ago
6 0
The reaction formula CH4 + 2O2 → CO2 + 2H2O shows the oxidation of 1 mole of CH4 (Methane) will yield 1 mole of CO2 (Carbon Dioxide). Since 1 mole of CH4 will weigh 12g (for the Carbon) + 4g (1g for each Hydrogen) = 16g, then 32g of CH4 will correspond to 32g / 16g/mole = 2 moles. Therefore the oxidation of 2 moles of CH4 will yield 2 moles of CO2.
Vikentia [17]1 year ago
4 0

Answer:

2.25 moles

Explanation:

thats correct answer

Thank you

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What is the concentration of a solution in which 10.0 g of AgNO3 is dissolved in 500 mL of solution?
Zigmanuir [339]

molar concentration of AgNO₃ solution = 0.118 mole/L

Explanation:

Because we have the volume of the solution and there is no information about the density of the solution I will asume that you ask for the molar concentration.

number of moles = mass / molecular weight

number of moles of AgNO₃ = 10 / 170 = 0.0588

molar concentration = number of moles / volume (L)

molar concentration of AgNO₃ solution = 0.0588 / 0.5

molar concentration of AgNO₃ solution = 0.118 mole/L

Learn more about:

molar concentration

brainly.com/question/1286583

#learnwithBrainly

6 0
3 years ago
What is the reactant(s) in the chemical equation below?
butalik [34]

Answer:

C. 3CO(g) + Fe2O3(s)

Explanation:

The substance(s) to the hath left of the arrow in a chemical equation art hath called reactants.  A reactant is a substance yond is presenteth at the starteth of a chemical reaction.  The substance(s) to the right of the arrow art hath called products.  A product is a substance yond is presenteth at the endeth of a chemical reaction

So in this example, 3CO(g) + Fe2O3(s) art the reactants.

The 2Fe(S) + 3CO2(G) art the products.

Desire I holp! Has't a most wondrous day!

Hope I helped!  Have a great day!

7 0
2 years ago
Calculate a reasonable amount (mass in g) of your unknown acid to use for a titration. You will want about 30 mL of titrant to g
Vinil7 [7]

Answer:

"0.60 g" is the appropriate solution.

Explanation:

The given values are:

Volume of base,

= 30 ml

Molarity of base,

= 0.05 m

Molar mass of acid,

= 400 g/mol

As we know,

⇒  Molarity=\frac{Number \ of \ moles \ of \ base}{Number \ of \ solution}

On substituting the values, we get

⇒           0.05=\frac{Number \ of \ moles \ of \ base}{30\times 10^{-3}}

⇒  Number \ of \ moles \ of \ base=0.05\times 30\times 10^{-3}

⇒                                             =1.5\times 10^{-3}  

hence,

⇒  Moles \ of \ acid=\frac{Mass \ of \ acid}{Molar \ mass \ of \ acid}

On substituting the values, we get

⇒  1.5\times 10^{-3}=\frac{Mass \ of \ acid}{400}

⇒  Mass \ of \ acid=1.5\times 10^{-3}\times 400

⇒                         =0.60 \ g

8 0
3 years ago
How much does one molecule of ethane (C2H6) weigh? anwser in units of g/molec.
Sladkaya [172]
30.07 g/mol (that’s grams per mole)
8 0
3 years ago
What’s the temperature at the boiling and freezing point of water in fanrenheit
Dominik [7]

Answer:

Boiling is 212* Freezing is 32*

Explanation:

It simple facts

5 0
2 years ago
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