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3 years ago

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4. The trajectory of a model rocket can be modelled by the equation h = - 3t^2 + 24t- 25, where h is the height of the rocket in

meters, and t is time after launch in seconds. Determine when the rocket is at the highest point.

1 answer:

Alex Ar [27]3 years ago

5 0

Answer:

It's too short. Write at least 20 characters to explain it well.

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Gnesinka [82]

The values of a and b are 1/4 and 1/5 respectively

<h3>How to determine the true statement?</h3>

The function is given as:

16x^2 - 25y^2 = 1

The above function is a horizontal hyperbola.

A horizontal hyperbola that passes through the origin is represented as:

$\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$

Rewrite 16x^2 - 25y^2 = 1 as

$\frac{x^2}{1/16} - \frac{y^2}{1/25} = 1$

By comparison, we have:

$a^2 = \frac{1}{16}$

$b^2 = \frac{1}{25}$

Solve for a and b

$a = \frac{1}{4}$

$b = \frac{1}{5}$

Hence, the values of a and b are 1/4 and 1/5 respectively

Read more about hyperbola at:

brainly.com/question/27799190

#SPJ1

7 0

2 years ago

PLSS PLSS HELP ME!!! I WILL MARK U!

ziro4ka [17]

The answer is
h= -41.36

You first multiply -8.1(-0.4) and you get 3.24.
Then you subtract 3.24 - 44.6 to get h.

8 0

3 years ago

If the ratio of corresponding segments is 2:3, then the ratios of the areas and volumes are

kobusy [5.1K]

Answer:

4:9

Step-by-step explanation:

Area is squaring and Volume is cubing

So it'd be 2^2:3^3, or 4:9

I hope this helped and have a good rest of your day!

6 0

3 years ago

Need help on this problem

vladimir2022 [97]

176.72 m^2 im thinking

5 0

4 years ago

Read 2 more answers

Please don’t judge me please if I don’t know

vladimir2022 [97]

Answer:

its ok

Step-by-step explanation:

there is this app called photo math where you take a picture of the problem and its answers you but the answer is -4g

8 0

3 years ago