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3 years ago

Dylan has a roll of wrapping paper that is5 meters long. How many centimeters of wrapping paper does he have.

Mathematics

1 answer:

In-s [12.5K]3 years ago

6 0

500 centimeters I think *sweats nervously*

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The engine torque y (in foot-pounds) of one model of car is given by y=−3.75x2+23.2x+38.8, where x is the speed (in thousands of

Stels [109]

Answer:

Step-by-step explanation:

If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8

The engine speed is at maximum if dy/dx = 0

dy/dx = -2(3.75)x+23.2

dy/dx = -7.5x + 23.2

since dy/dx = 0

0 = -7.5x + 23.2

7.5x = 23.2

x = 23.2/7.5

x = 3.093

Hence the maximum torque is 3.09 rev/min

8 0

3 years ago

PLEASE I NEED HELP ILL MARK AS BRAINLIEST

Papessa [141]

Answer:

Ali´s secret number is 13

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Dan got a discount of 4/5 on his grocery bill by using his club card and coupons Emile got a discount of 7/10,Alina got a discou

Grace [21]

Answer:

it is dan

Step-by-step explanation:

because 4/5 is the closest to 1.

3 0

4 years ago

Solve the system: 2/x - 3/y =-5; 4/x + 6\y =14

sertanlavr [38]

The solution is $x = 2 \text{ and } y = \frac{1}{2}$

Solution:

Let us assume,

$a = \frac{1}{x}\\\\b = \frac{1}{y}$

Given system of equations are:

$\frac{2}{x} - \frac{3}{y} = -5$

$\frac{4}{x} + \frac{6}{y} = 14$

Rewrite the equation using "a" and "b"

2a - 3b = -5 ------------ eqn 1

4a + 6b = 14 -------------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 2

2(2a - 3b = -5)

4a - 6b = -10 ------------- eqn 3

Add eqn 2 and eqn 3

4a + 6b = 14

4a - 6b = -10

( - ) --------------------

8a = 4

$a = \frac{4}{8}\\\\a = \frac{1}{2}$

Substitute a = 1/2 in eqn 1

$2(\frac{1}{2}) -3b = -5\\\\1 - 3b = -5\\\\3b = 6\\\\b = 2$

Now let us go back to our assumed values

Substitute a = 1/2 in assumed values

$a = \frac{1}{x}\\\\\frac{1}{2} = \frac{1}{x}\\\\x = 2$

Substitute b = 2 in assumed value

$b = \frac{1}{y}\\\\2 = \frac{1}{y}\\\\y = \frac{1}{2}$

Thus the solution is $x = 2 \text{ and } y = \frac{1}{2}$

3 0

3 years ago

NEED HELP FAST

Natasha_Volkova [10]

Your answer is C :) blessings

5 0

3 years ago