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3 years ago

Can someone help me with this

Mathematics

1 answer:

Alexandra [31]3 years ago

3 0

Answer:

Step-by-step explanation:

The formula for this, specific to our circle, is

∠RQP = $\frac{1}{2}$ (arc SP - arc RP) and filling in:

∠RQP = $\frac{1}{2}(170-86)$ and

∠RQP = $\frac{1}{2}(84)$ so

∠RQP = 42°

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Please help. I’ll mark you as brainliest if correct!

beks73 [17]

Answer:

x and y can have many values

Step-by-step explanation:

-24x - 12y = -16

Then: 24x + 12y = 16

We know: 6x + 3y = 4

X and Y can have a lot of valoues.

6x + 3y = 4

3 ( 2x + y) = 4

2x + y= 4/3

2x+y= 1.333...

6 0

3 years ago

Help meee I’ll give 10 pts and brainliest!!!

crimeas [40]

Step-by-step explanation:

i) $\overline{AB} = \sqrt{(x_A - x_B)^2 + (y_A - y_B)^2}$

$\:\:\:\:\:\:\:=\sqrt{(2)^2 + (12)^2} = 12.3$

ii) $m = \dfrac{y_A - y_B}{x_A - x_B} = \dfrac{-12}{2} = -6$

iii) $(\overline{x},\:\overline{y}) = \left(\dfrac{x_A + x_B}{2},\:\dfrac{y_A + y_B}{2}\right)$

$\:\:\:\:\:\:\:=(3,\:-2)$

7 0

3 years ago

List all factor for each number 100. 65. 70

LiRa [457]

The factors of 100 are 1, 2, 4, 5, 10, 20, 25, 50, and 100 .

The factors of 65 are 1, 5, 13, and 65 .

The factors of 70 are 1, 2, 5, 7, 10, 14, 35, and 70 .

3 0

3 years ago

Read 2 more answers

Fibonacci posed the following problem: Suppose that rabbits live forever and that every month each pair produces a new pair whic

docker41 [41]

Answer:

Let f_n be the number of rabbit pairs at the beginning of each month. We start with one pair, that is f_1 = 1. After one month the rabbits still do not produce a new pair, which means f_2 = 1. After two months a new born pair appears, that is f_3 = 2, and so on. Let now n $\geq$ 3 be any natural number. We have that f_n is equal to the previous amount of pairs f_n-1 plus the amount of new born pairs. The last amount is f_n-2, since any two month younger pair produced its first baby pair. Finally we have

f_1 = f_2 = 1,f_n = f_n-1 + f_n-2 for any natural n $\geq$ 3.

5 0

3 years ago

According to the United Nations, in the year 2002, the population of the world was 6.1 billion people and was growing at an annu

zmey [24]

Answer:

(a) 6.2843 billion

(b) 6.8716 billion

Step-by-step explanation:

Since there is a constant growth rate of 1.5% per year, and the population in 2002 was 6.1 billion people. The general equation for the total world population, in billions, after 2002 is:

$P(t) = 6.1*(1+0.015)^t$

With t being the time, in years, after 2002.

a) What was the population in 2004?

$t=2004-2002=2\\P(2) = 6.1*(1.015)^2\\P(2) = 6.2843 \ billion$

b) What was the population in 2010?

$t=2010-2002=8\\P(8) = 6.1*(1.015)^8\\P(8) = 6.8716 \ billion$

3 0

3 years ago