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2 years ago

10

130 is to be divided among three restaurant servers. Angie made $30 more than Marie. Gwen, who went home sick, made $35 less tha

n Marie. How
much money should each server get

1 answer:

Margarita [4]2 years ago

3 0

Answer:

be smart you will knoow thanks for the free ppints hahaha

Step-by-step explanation:

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Thirty-two cyclists make a seven-day trip. Each cyclist requires 8.33 kilograms of food for the entire trip. If each cyclist wan

kvasek [131]

Answer:

76.16 kilograms of food

Step-by-step explanation:

Number of cyclist = 32

Food per cyclist = 8.33 kilograms

Days of the trip = 7 days

Food per cyclist per day = 8.33 kg / 7

= 1.19kg food per day for each cyclist

how many kilograms of food will the group be carrying at the end of Day 5?

5 days out of 7 days = 2 days

Each cyclist will have to carry = 2 × 1.19 kg of food for the remaining two days

= 2 × 1.19

= 2.38 kilograms of food for two days

32 cyclist for 2 days = 32 × 2.38 kg of food

= 76.16 kilograms of food

The group will be carrying 76.16 kilograms of food at the end of Day 5

3 0

2 years ago

Pls help me!!! ( pls dont answer if you don’t have the answer I will report you ...).

bezimeni [28]

I think 517.26
I did 10 times 3^2 (9) it equals 90. Then 90 times 3.14 and got 282.74. Then did 800- 282.74 and got 517.26

5 0

2 years ago

Read 2 more answers

You (or your parents) were purchasing a used car. Which interests rate do you use?<br>

Marina CMI [18]

New secured 4.5 is the best option

7 0

2 years ago

The following lists the joint probabilities associated with smoking and lung disease among 60-to-65 year-old men. Has Lung Disea

Anna71 [15]

Answer:

4.11% probability that he has lung disease given that he does not smoke

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Does not smoke

Event B: Lung disease

Lung Disease/Nonsmoker 0.03

This means that $P(A \cap B) = 0.03$

Lung Disease/Nonsmoker 0.03

No Lung Disease/Nonsmoker 0.7

This means that $P(A) = 0.03 + 0.7 = 0.73$

What is the probability of the following event: He has lung disease given that he does not smoke?

$P(B|A) = \frac{0.03}{0.73} = 0.0411$

4.11% probability that he has lung disease given that he does not smoke

5 0

2 years ago

The scatter plot below shows the distances some employees of a company commute to work and the annual

salantis [7]

Answer:

It is a

Step-by-step explanation: I looked it up

6 0

2 years ago