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3 years ago

PLEASEEE HELP ASAPPPP . When solving using Elimination:

Mathematics

1 answer:

Komok [63]3 years ago

6 0

Y because if you add them you will get 10x =-10
The y will be eliminated because you have positive 3 -4

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Graph the inequality x>-8 using the steps

Yuki888 [10]

Hey!

Your point on the graph would be ( -8, 0 ).

We shade the right side of the graph because the inequality shows that x is greater than -8.

*SEE THE GRAPH BELOW*

Hope this helps!

- Lindsey Frazier ♥

3 0

3 years ago

Write an equation in slope-intercept form of the line with the parametric equations x=2t and y=1-t

pentagon [3]

Answer: -x/2 + 1

Step-by-step explanation:

write t in terms of x

x = 2t

t = x/2

substitute t in y

y = 1 - t

y = 1 - x/2 or -x/2 + 1

6 0

3 years ago

Read 2 more answers

Martin is seating people in the cars of a roller coaster. Each car can seat 8 people. Six of the roller coaster cars are yellow

Mamont248 [21]

Answer:

The probability is 2/5

Step-by-step explanation:

Here, we want to calculate the probability that the first person will sit in a yellow roller coaster car

The number of cars to select from is 6 + 9 = 15 cars

The number of yellow cars is 6

So the probability that the first person selects a yellow roller coaster car to seat is 6/15 = 2/5

5 0

3 years ago

The pirouette dance team needs more than $300 to cover

noname [10]

Answer:

You need "more than" 300.

Step-by-step explanation:

i did the test

8 0

2 years ago

Helppp me plsssssssss<br><br>

Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

$\sf \:\:\:\:\:\:\:\:\:\:x_{k}=35$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k}=50$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42$
$\sf \:\:\:\:\:\:\:\:\:\:h=5$

${\bf \:\: {By\:using\:the\: formula}} \\ \\$

$\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\$

$\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\$

${\large{\frak{\pmb{\underline{Additional\: information }}}}}$

MODE

Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

In a frequency distribution the class having maximum frequency is called the modal class.

${\bf{\underline{Formula\:for\: calculating\:mode:}}} \\$

${\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\$

Where,

$\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.$

$\small \blue{ \bigstar}$ $\sf \: f_{k}=frequency\:of\:the\:modal\:class$

$\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class$

$\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class$

$\small \purple{ \bigstar}$ $\sf \: h= width \:of\:the\:class\:interval$

7 0

3 years ago