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3 years ago

6

Find the measure of angle A Plss help luvs

1 answer:

neonofarm [45]3 years ago

5 0

Step-by-step explanation:

Since the given triangle is rt.angled triangle,

or,x+35+x+65=90

or,2x+100=90

or,2x=-10

or,x=-5

Angle A=x+35

=-5+35

=30°

please give brainliest .if u have any questions related to this solution then u can ask in comment box.

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The total cost of an item including sales tax is directly proportional to its price. If the total cost of a $32 item is $33.60 ,

pav-90 [236]

Let the total cost of the item be represented by C and the price be represented by P, then given that t<span>he total cost of an item including sales tax is directly proportional to its price, thus</span>

$C\propto P \\ \\ \Rightarrow C=kP$

where k is a constant.

Given that <span>the total cost of a $32 item is $33.60, thus

$33.60=32k \\ \\ \Rightarrow k= \frac{33.60}{32} =1.05$

Therefore, the total cost on a $55 item is given by

$C=1.05\times55=\$57.75$ </span>

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4 years ago

19. For livesh's Model A rocket, he uses the equation h=-490^2+ 1120t. When is the height of the Model A rocket 640 centimeters?

Nadusha1986 [10]

Answer:

t = 1.143 s

Step-by-step explanation:

The equation he uses to model the height of the rocket in cm, as function of time is

h(t) = -490 t^2 + 1120t

We can plot this equation using a graphing tool

Please, see attached picture

The rocket reaches his maximum height (640 cm) at

t = 1.143 s

5 0

3 years ago

As notas de dois alunos X e Y estão representadas no quadro abaixo. Por meio da variância, qual deles apresentou ser o mais regu

Reil [10]

Answer:

Aluno X

Step-by-step explanation:

A nota média para os alunos X e Y são, respectivamente:

$X_m=\frac{5+3+5+7}{4}=5 \\Y_m=\frac{4+9+4+3}{4}=5$

A variância é definida pela seguinte expressão:

$V=\frac{\sum(X_i-X_m)^2}{n-1}$

Onde n é o numero de termos, neste caso, n = 4.

As variâncias para cada aluno são:

$V_x=\frac{(5-5)^2+(3-5)^2+(5-5)^2+(7-5)^2}{4-1} \\V_x= 2.7\\V_y=\frac{(4-5)^2+(9-5)^2+(4-5)^2+(3-5)^2}{4-1} \\V_y= 7.3$

O aluno X apresentou uma variância menor do que o aluno Y em suas notas e, portanto, apresentou ser o mais regular.

6 0

3 years ago

Need help with this please

AysviL [449]

choice a is the correct answer

5 0

3 years ago

The time between surface finish problems in a galvanizing process is exponentially distributed with a mean of 41 hours. A single

Lubov Fominskaja [6]

Answer:

a) The probability that none of the lines experiences a surface finish problem in 41 hours of operation is 0.0498.

b)The probability that all three lines experience a surface finish problem between 24 and 41 hours of operation is 0.0346.

Step-by-step explanation:

$Mean = \frac{1}{\lambda} = 41\\P(X\leq x)= 1-e^{-\lambda x}$

$P(X>x)= e^{-\lambda x}$

a)

$P(x> 41, y>41, Z>41) = (P(X>41))^{3}\\\\P(X>41)=e^{^{-\frac{41}{41}}}=e^{-1}$

$P(x> 41, y>41, Z>41) = \left (e^{-1} \right )^{3}\\\\P(x> 41, y>41, Z>41) = e^{-3} = 0.0498.$

b)

$\lambda =\frac{24}{41}\\P(X=1)=e^{-\lambda }\cdot \lambda =\left ( e^{-0.585} \right )\left ( 0.585 \right )\\P(X=1)=0.326$

For 3 where, P(X=1, Y==1, Z=1)

$= (0.326)^{3} \\\\= 0.0346$

4 0

3 years ago