Answer:
5
Step-by-step explanation:
There are 5 faces on a square pyramid
Answer: The required solution is 
Step-by-step explanation:
We are given to solve the following differential equation :

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.
From equation (i), we have

Integrating both sides, we get
![\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]](https://tex.z-dn.net/?f=%5Cint%5Cdfrac%7Bdy%7D%7By%7D%3D%5Cint%20kdt%5C%5C%5C%5C%5CRightarrow%20%5Clog%20y%3Dkt%2Bc~~~~~~%5B%5Ctextup%7Bc%20is%20a%20constant%20of%20integration%7D%5D%5C%5C%5C%5C%5CRightarrow%20y%3De%5E%7Bkt%2Bc%7D%5C%5C%5C%5C%5CRightarrow%20y%3Dae%5E%7Bkt%7D~~~~%5B%5Ctextup%7Bwhere%20%7Da%3De%5Ec%5Ctextup%7B%20is%20another%20constant%7D%5D)
Also, the conditions are

and

Thus, the required solution is 
Answer:
Step-by-step explanation:
Total number of pairs of socks in a drawer = 10
Number of black pairs of socks = 5
Number of blue pairs of socks = 5
A. If you picked 2 socks [black] and [blue] 3rd pick guarantees you will have one pair of either blue or black
Number of socks you pull out to guarantee that you have a pair of one color = 3 socks
B. If you want to pick 2 good pairs and your 6 picks are worst case, so 7th pick of the socks will give you good pair of two colors.
Number of socks you pull out to have two good pairs = 7 socks
C. If you want to have a pair of black socks your worst case will be you pick all 10 blue socks so another 2 socks must be black.
Number of socks you pull out to have two black socks = 12 socks
Answer:
im in ur math class dawg lol
Step-by-step explanation: