Answer:
A. 26.10 cm
B. 118.95 cm
Step-by-step explanation:
ST = 41^2 - 40^2 = c^2 = hypotenuse
ST = 1681 - 1600 = c^2
ST = c^2 = sq rt 681 =26.0959767014 = 26.1cm
Nearest 100th = 26.10
Length = 26.10 cm to nearest 100th
Perimeter of RSU we find (M) of SU first then add that to the other 3 lengths on the exterior of the triangle.
SU = 10^2 + 26.1^2 = c^2 = hypotenuse
SU = 100 + 681.21 = c^2
SU = c^2 = sqrt 781.21 = 27.9501341678 = 27.95cm
P TOTAL RSU = SU + TR + RS + TU
= 27.95 + 40+ 41 + 10 = 118.95cm
<span>-3(2m-1)-n
First we multiply -3 to the first term of the expression
---------- > ( -3*2m + (-3)*(-1) ) - n
</span>---------- > ( -6m + 3 ) - n<span>
-----------> -6m -n + 3
Then, we divide and multiply by -6, (the expression remains the same)
</span>
---- > (-6/-6)* (-6m -n + 3)<span>
---- > -6*[m + (n/6) - 1/2]
</span>
The answer is -6*[m + (n/6) - 1/2]
Answer:
Translation
Step-by-step explanation:
Transformation is the movement of objects in the coordinate plane. It can be through any of translation, reflection or rotation. The kind of transformation that occurs in ordered pairs is translation e.g if the ordered pair is (1, 4) x = 1, while y = 4. if it is translated we have (4, 1) such that x is now 4 while y is 1
Answer:
5 hours
Step-by-step explanation:
bro all your doing is adding 2 and 3
Answer:
Step-by-step explanation:
From the question attached,
Given:
RT and PQ intersect at a point S.
RS = PS and ST = SQ
To prove :
RT = PQ
Statements Reasons
1). RS = PS and ST = SQ 1). Given
2). RS + ST = PS + SQ 2). Addition property
3). RS + ST = RT ; PS + SQ = PQ 3). Pair of line segments
4). RT = PQ 4). Substitution property
