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yKpoI14uk [10]
2 years ago
14

Which correlation coefficient would most likely show a weak negative association?

Mathematics
1 answer:
choli [55]2 years ago
8 0

Answer:

Step-by-step explanation:

We can use the regression line to model the linear relationship between x and y ... x and y because the correlation coefficient is not significantly different from zero. ... If r is significant and the scatter plot shows a linear trend, the line can be used to ... If r < negative critical value or r > positive critical value, then r is significant.

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Pls help its timed!!​
zalisa [80]
I believe it’s A
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3 0
3 years ago
C=2(3.14)r solve for r
Neporo4naja [7]
<span>C=2(3.14)r 
C = 6.28r
r = C / 6.28

hope it helps</span>
7 0
3 years ago
Read 2 more answers
Find the surface area of the rectangular box below
REY [17]

Answer:

SA = 904 in.²

Step-by-step explanation:

Surface Area (SA) of a cuboid: 2(lw) + 2(wh) + 2(hl)

SA = 2(lw) + 2(wh) + 2(hl)

  • l = 36 in.
  • w = 10 in.
  • h = 2 in.

Substitute the given values and multiply:

SA = 2(lw) + 2(wh) + 2(hl)

SA = 2(36)(10) + 2(10)(2) + 2(2)(36)

SA = 2(360) + 2(20) + 2(72)

SA = 720 + 40 + 144

SA = 904 in.²

Hope this helps!

5 0
1 year ago
There are two calculus classes at your school. Both classes have a class average of 75.5. The first class has a standard deviati
Korvikt [17]
To compare the two classes, the Coefficient of Variation (COV) can be used. The formula for COV is this:
C = s / x
where s is the standard deviation and x is the mean
For the first class:
C1 = 10.2 / 75.5
C1 = 0.1351 (13.51%)

For the second class:
C2 = 22.5 / 75.5
C2 = 0.2980 (29.80%)

The COV is a test of homogeneity. Looking at the values, the first class has more students having a grade closer to the average than the second class.
4 0
2 years ago
Greenfields is a mail order seed and plant business. The size of orders is uniformly distributed over the interval from $25 to $
LekaFEV [45]

Answer:

a) 47.55

b) 58

c) 47.88

Step-by-step explanation:

Given that the size of the orders is uniformly distributed over the interval

$25 ( a ) to $80 ( b )

<u>a) Determine the value for the first order size generated based on 0.41</u>

parameter for normal distribution is given as ;  a = 25,  b = 80

size/value of order  = a + random number ( b - a )

                                = 25 + 0.41 ( 80 - 25 )

                                =  47.55

<u>b) Value of the last order generated based on random number (0.6)</u>

= a + random number ( b - a )

= 25 + 0.6 ( 80 - 25 )

= 25 + 33 = 58

<u>c) Average order size </u>

= ∑ order 1 + order 2 + ----- + order 10  ) / 10

= (47.55 + ...... + 58 ) / 10

= 478.8 / 10 = 47.88

4 0
3 years ago
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