I believe it’s A
Writing random things so it lets me send this
<span>C=2(3.14)r
C = 6.28r
r = C / 6.28
hope it helps</span>
Answer:
SA = 904 in.²
Step-by-step explanation:
Surface Area (SA) of a cuboid: 2(lw) + 2(wh) + 2(hl)
SA = 2(lw) + 2(wh) + 2(hl)
- l = 36 in.
- w = 10 in.
- h = 2 in.
Substitute the given values and multiply:
SA = 2(lw) + 2(wh) + 2(hl)
SA = 2(36)(10) + 2(10)(2) + 2(2)(36)
SA = 2(360) + 2(20) + 2(72)
SA = 720 + 40 + 144
SA = 904 in.²
Hope this helps!
To compare the two classes, the Coefficient of Variation (COV) can be used. The formula for COV is this:
C = s / x
where s is the standard deviation and x is the mean
For the first class:
C1 = 10.2 / 75.5
C1 = 0.1351 (13.51%)
For the second class:
C2 = 22.5 / 75.5
C2 = 0.2980 (29.80%)
The COV is a test of homogeneity. Looking at the values, the first class has more students having a grade closer to the average than the second class.
Answer:
a) 47.55
b) 58
c) 47.88
Step-by-step explanation:
Given that the size of the orders is uniformly distributed over the interval
$25 ( a ) to $80 ( b )
<u>a) Determine the value for the first order size generated based on 0.41</u>
parameter for normal distribution is given as ; a = 25, b = 80
size/value of order = a + random number ( b - a )
= 25 + 0.41 ( 80 - 25 )
= 47.55
<u>b) Value of the last order generated based on random number (0.6)</u>
= a + random number ( b - a )
= 25 + 0.6 ( 80 - 25 )
= 25 + 33 = 58
<u>c) Average order size </u>
= ∑ order 1 + order 2 + ----- + order 10 ) / 10
= (47.55 + ...... + 58 ) / 10
= 478.8 / 10 = 47.88
