Which question in order for me 2 answer
Answer:42
Step-by-step explanation:
9514 1404 393
Answer:
14.14
Step-by-step explanation:
The diagonal of a square is √2 times the side length.
AC = AB×√2
AC = 10√2 ≈ 14.14
_____
The diagonal of a square is the hypotenuse of an isosceles right triangle. If the sides of that are s and the diagonal is d, the Pythagorean theorem tells us ...
d² = s² + s²
d² = 2s²
d = (√2)(√s²) = s√2
This relation holds for <em>any isosceles right triangle</em>, not just for the diagonal of this square. It is useful to remember.
find the mean, median, and interquartile range for the data set below. 5,8,9,11,13,15,16,17,17,18,22,23
Alekssandra [29.7K]
Answer:
Mean: 14.5
Median: 15.5
IQR = 7.5
Step-by-step explanation:
For mean:
Mean= (∑x)/n
=(5+8+9+11+13+15+16+17+17+18+22+23)/12
= 174/12
=14.5
Median:
As the data is already sorted and the number of items are odd, average of two middle values will be the median of the data.
5,8,9,11,13,15,16,17,17,18,22,23
Median=(15+16)/2
=31/2
=15.5
IQR:
For IQR, the data has to be divided in two parts, lower and upper, then we have to find the median of both parts separately. The difference of medians of both parts is called the Interquartile range.
So for lower part,
5,8,9,11,13,15
Median for lower part= (9+11)/2
= 20/2
=10
For upper part:
16,17,17,18,22,23
Median for lower part= (17+18)/2
= 35/2
=17.5
IQR=17.5-10
=7.5
