What is a synthetic division used for

Rewrite 2/4 : 1/8 as a unit rate WILL GIVE BRAINLIEST

photoshop1234 [79]

This is a fraction equal to
2 1 ÷ 4 8

We want a unit rate where
1 is in the denominator,
so we divide top and bottom by 4

2 1 ÷ 4
4 8 ÷ 4
=
0.5 1
1 8
=
0.5 1
8
= 0.5 1 per 8

6 0

3 years ago

Given that 2x^2 - 2y^2 = 40 and x-y=5, find the value of (x+y)

kipiarov [429]

Answer:

x+y=4

Step-by-step explanation:

hello :

note : by identity you have x²-y² = (x-y)(x+y)

in this exercice : 2x²-2y² = 2(x²-y²) = 2 (x-y)(x+y)

means : 2 (x-y)(x+y) = 40

but x-y = 5

so : 2(5)(x+y) =40

x+y=40/10

x+y=4

5 0

2 years ago

Plz help me well mark brainliest if correct!....

Brums [2.3K]

Its B! They have to multiply to get 96 and b is the only one that also adds to get 40

5 0

3 years ago

I need help ASAP!

Readme [11.4K]

Answer:

i) Equation can have exactly 2 zeroes.

ii) Both the zeroes will be real and distinctive.

Step-by-step explanation:

$x^{2} - 7x + 3$ is the given equation.

It is of the form of quadratic equation $a^{2} + bx + c$ and highest degree of the polynomial is 2.

Now, FUNDAMENTAL THEOREM OF ALGEBRA

If P(x) is a polynomial of degree n ≥ 1, then P(x) = 0 has exactly n roots, including multiple and complex roots.

So, the equation can have exact 2 zeroes (roots).

Also, find discriminant D = $b^{2} - 4ac = (-7)^{2} - 4(1)(3) = 49 - 12 = 37$

⇒ D = 37

Here, since D > 0, So both the roots will be real and distinctive.

7 0

3 years ago

. Given ????(5, −4) and T(−8,12):

damaskus [11]

Answer:

a) $y=\dfrac{13x}{16}-\dfrac{129}{16}$

b) $y = \dfrac{13x}{16}+ \dfrac{37}{2}$

Step-by-step explanation:

Given two points: $S(5,-4)$ and $T(-8,12)$

Since in both questions,a and b, we're asked to find lines that are perpendicular to ST. So, we'll do that first!

Perpendicular to ST:

the equation of any line is given by: $y = mx + c$ where, m is the slope(also known as gradient), and c is the y-intercept.

to find the perpendicular of ST we first need to find the gradient of ST, using the gradient formula.

$m = \dfrac{y_2 - y_1}{x_2 - x_1}$

the coordinates of S and T can be used here. (it doesn't matter if you choose them in any order: S can be either x_1 and y_1 or x_2 and y_2)

$m = \dfrac{12 - (-4)}{(-8) - 5}$

$m = \dfrac{-16}{13}$

to find the perpendicular of this gradient: we'll use:

$m_1m_2=-1$

both $m_1$ and $m_2$ denote slopes that are perpendicular to each other. So if $m_1 = \dfrac{12 - (-4)}{(-8) - 5}$ , then we can solve for $m_2$ for the slop of ther perpendicular!

$\left(\dfrac{-16}{13}\right)m_2=-1$

$m_2=\dfrac{13}{16}$ :: this is the slope of the perpendicular

a) Line through S and Perpendicular to ST

to find any equation of the line all we need is the slope $m$ and the points $(x,y)$ . And plug into the equation: $(y - y_1) = m(x-x_1)$

side note: you can also use the $y = mx + c$ to find the equation of the line. both of these equations are the same. but I prefer (and also recommend) to use the former equation since the value of 'c' comes out on its own.

$(y - y_1) = m(x-x_1)$

we have the slope of the perpendicular to ST i.e $m=\dfrac{13}{16}$