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raketka [301]
2 years ago
8

If f(x)=-x^2+2x, find f(3)-7

Mathematics
1 answer:
igomit [66]2 years ago
5 0

Answer:

f(3) just means to substitute 3 in for x.

Step-by-step explanation:

f(3) just means to substitute 3 in for x.  

f

(

3

)

=

−

2

Explanation:

f

(

3

)

=

−

(

3

)

2

+

7

According to the order of operations, first square the 3, which is 9.

f

(

3

)

=

−

9

+

7

The negative sign in front of the x squared is equivalent to multiplying by negative one.

Add -9 and 7 together, which is -2

So,  

f

(

3

)

=

−

2

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Step-by-step explanation:

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Write an equivalent expression to present patricia total earnings this week 7h + 135 + 5h = ?h + ?​
Paul [167]

Answer: 12 h + 135

Step-by-step explanation: 7h +135 + 5h = ?h + ?​

                                             7h +5h +135  

                                            =12h +135

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Ps.If you don't know what like terms are.I will explain down below.

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8 0
2 years ago
A machine, when working properly, produces 5% or less defective items. Whenever the machine produces significantly greater than
vovikov84 [41]

Answer:

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

Step-by-step explanation:

A machine, when working properly, produces 5% or less defective items.

This means that the null hypothesis is:

H_0: p \leq 0.05

Test if the percentage of defective items produced by this machine is greater than 5%.

This means that the alternate hypothesis is:

H_a: p > 0.05

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.05 is tested at the null hypothesis:

This means that \mu = 0.05, \sigma = \sqrt{0.05*0.95}

A random sample of 300 items taken from the production line contained 27 defective items.

This means that n = 300, X = \frac{27}{300} = 0.09

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.09 - 0.05}{\frac{\sqrt{0.05*0.95}}{\sqrt{300}}}

z = 3.18

Pvalue of the test:

Testing if the mean is greater than a value, which means that the pvalue of the test is 1 subtracted by the pvalue of Z = 3.18, which is the probability of a finding a sample proportion of 0.09 or higher.

Looking at the Z-table, Z = 3.18 has a pvalue of 0.9993

1 - 0.9993 = 0.0007

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

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