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1 year ago

Find x if the ekvation is x-3x+7x/2-1=9

Mathematics

1 answer:

sladkih [1.3K]1 year ago

4 0

Step-by-step explanation:

i got confused whether it is 7/2 or /2-1

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Need help loveliesss

tiny-mole [99]

P=44.6

P=a+b+√a^2+b^2=11+15+√11^2+15^2≈44.6

3 0

2 years ago

In a packet of stickers there are 15 small stars, 7 big stars, 9 small rockets, and 6 big rockets. Kevin is going to choose one

yanalaym [24]

Answer:

31/37

Step-by-step explanation:

There are 15 + 7 + 9 + 6 = 37 total stickers. Of those, 15 + 9 = 24 are small and 15 + 7 = 22 are stars. However, there are 15 small stars so 24 - 15 = 9 of them are only small and 22 - 15 = 7 are only stars. This means that there are 15 + 9 + 7 = 31 stickers that are small or stars, therefore the probability is 31/37.

4 0

2 years ago

Find the slope of every line that is parallel to the graph of the equation x+7y=6

raketka [301]

$x+7y=6

7y=-x+6

(7y)/7=(-x+6)/7

y=(-1/7)x+6/7


Since, y=mx+b and m is the slope

m=-1/7$

7 0

2 years ago

A cylinder has a radius of 3 and a height of 4 Using 3.14 (pi) Round your answer to the nearest hundredth What is the volume of

tensa zangetsu [6.8K]

Answer:

113.04 cubic units. ".04" is four hundredths.

(the units are not given here. They could be cubic feet, cubic inches, cubic meters, cubic centimeters. or other measurements.)

Step-by-step explanation:

To find volume we need to multiply the area of the base times the height.

The base of a cylinder is a circle.

The area is πr²

The given radius here is 3

3² is 9

π × 9 using 3.14 is 28.26

Multiply that area by the given height, 4

28.26 × 4 = 113.04

The volume if this cylinder is 113.04 cubic units.

6 0

2 years ago

We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure

STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be $h(t) = -16\cdot t^{2} + 128\cdot t + 320$ , the first and second derivatives are, respectively:

First Derivative

$h'(t) = -32\cdot t +128$

Second Derivative

$h''(t) = -32$

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

$-32\cdot t +128 = 0$

$t = \frac{128}{32}\,s$

$t = 4\,s$ (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

$h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320$

$h(4\,s) = 576\,ft$

The highest altitude that the object reaches is 576 feet.

6 0

3 years ago