All categories

4 years ago

What is the probability that a couple will have a girl a boy a girl and a boy in this specific order?

1 answer:

3 0

P(boy)=1/2
P(girl)=1/2
P(a girl, a boy , a girl and a boy)=1/2*1/2*1/2*1/2= 1/16
P(2 boys and 2 girls ) = 1/[4!/(2!*2!)] =1/6

hope this helps u

You might be interested in

Solve for x (3x+5)+(4x+1)

DENIUS [597]

X=12

7X+6=90

7X=84

X=12

4 0

4 years ago

Solve for w. 2w=12-4w Simplify your answer as much as possible.

aev [14]

So we have an equation:
2w=12-4w
Firstly, let's simplify, and divide all terms by 2:
w=6-2w
Now, we add 2w over to the other side:
3w=6
And finally, we divide both sides by 3:
w=2
Hope this helps!

6 0

4 years ago

What is the value in the figure above?

Elan Coil [88]

Answer: i can’t read it could try upload it again

Explanation: Henlo :3

6 0

3 years ago

Read 2 more answers

A number is 6 greater than 1/2 another number. If the sum of the numbers is 21,find the numbers.

Fed [463]

X = (1/2)y + 6
x + y = 21

Substitute (1/2)y + 6 as x into the equation x + y = 21 since x = (1/2)y + 6.
[(1/2)y + 6] + y = 21
0.5y + 6 + y = 21
1.5y = 15
y = 10

Same thing, now substitute 10 as y in the other equation.
x + y = 21
x + (10) = 21
x = 11

7 0

3 years ago

Help me ASAP!!!!!!!!

larisa [96]

Step-by-step explanation:

a) The rule is multiply the previous term by 6 then add 13. So if the 1st term is n0 = -2, then the next term n1 is

n1 = 6n0 + 13

= 6(-2) + 13

= 1

n2 = 6n1 + 13

= 6(1) + 13

= 19

So the sequence goes like

-2, 1, 19

b) Now the sequence is reversed so let's write the terms as follows:

19, 1, -2

The new rule now is subtract 13 then divide by 6. You can check this as follows:

n0 = 19

n1 = (n0 - 13)/6

= (19 - 13)/6

= 1

n2 = (n1 - 13)/6

= (1 - 13)/6

= -2

5 0

3 years ago