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Ludmilka [50]
3 years ago
10

The pool at a resort needs a fence added around its lounge area for safety. The pool measures 20 feet by 40 feet and the lounge

area is 10 feet on each side of the pool. How much fence is needed to go around all four sides of the lounge area?
Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
3 0

Answer:

The amount of fence needed to surround the mentioned space is:

  • <u>200 feet</u>.

Step-by-step explanation:

To identify the amount of fence, you must take all the measurements given in the exercise:

  • Pool width = 20 ft
  • Pool length = 40 ft
  • Aditional area in each side = 10 ft

As each side has 10 additional feet, that is the lounge area, you must add 20 feet to each side of the pool, this is because, in the case of the width, you must add 10 feet to the right side and 10 feet to the left side, in the case of the length, you must add to each side 10 feet to the upper part and 10 feet to the lower part, in this form, the measurements of the fence must be:

  • Width of fenced area = 40 ft
  • Length of fenced area = 60 ft

As you know, the length has two sides and the length has two sides too, by this reason, we must multiply each value by 2 to obtain the amount of fence  to all four sides of the lounge area:

  • Amount of fence = 2(40 ft) + 2(60 ft)
  • Amount of fence = 80 ft + 120 ft
  • <u>Amount of fence = 200 ft</u>

As you can see, <u><em>the amount of fence needed to go around the lounge area is 200 feet</em></u>.

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Answer:

m∠1 = 39.5°

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A study found that 1% of Social Security recipients are too young to vote. If 800 social security recipients are randomly select
GalinKa [24]

Answer:

8, 7.92, 2.81

Step-by-step explanation:

For each Social Security recipient, there are only two possible outcomes. Either they are too young to vote, or they are not. The probability of a Social Security recipient is independent of any other Social Security recipient. So we use the binomial probability distribution to solve this question.

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The expected value of the binomial distribution is:

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The variance of the binomial distribution is:

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The standard deviation of the binomial distribution is:

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The standard deviation of the binomial distribution is:

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