Answer:
Look at the picture. The answer and the steps are all in it.
1+tan^2(A) = sec^2(A) [Pythagorean Identities]
tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)
*see photo for complete solution*
Let +n+ = number of bottles of cranberry juice needed
+2n+ = number of bottles of ginger ale needed
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+3.2n+%2B+.9%2A%28+2n+%29+=+20+
+3.2n+%2B+1.8n+=+20+
+32n+%2B+18n+=+200+
+50n+=+200+
+n+=+4+
and
+2n+=+8+
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The most bottles of cranberry juice is 4
Answer:
288
Explanation:
As first term in sequence is 3 so multiplying it by common ratio 5 we get 15, then multiplying 15 by 5 we get 45 and so on the sequence is
<span>3,15,45,225</span>
whose sum is 288
Answer:
n = 5
Step-by-step explanation:
Given
n + 16 = 21 ( isolate n by subtracting 16 from both sides )
n = 5