A negative exponent means the number of the exponent divide by the number. The the radius of beryllium atom is larger than the radius of a nitrogen atom by two times.
Given information-
The radius of a nitrogen atom is
meters.
The radius of a beryllium atom is
meters
<h3>Negative exponents</h3>
A negative exponent means the number of the exponent divide by the number.
As the radius of the nitrogen atom is
meters. Convert it in the power of negative exponent of 10.
Let the radius of the nitrogen is
mm. Thus,
![r=5.6\times 10^{-11}\\ r=5.6\times 10^{-10-1}\\ r=5.6\times 10^{-10}\times10^{-1}\\ r=\dfrac{5.6\times 10^{-10}}{10} \\ r=0.56\times 10^{-10}](https://tex.z-dn.net/?f=r%3D5.6%5Ctimes%2010%5E%7B-11%7D%5C%5C%0Ar%3D5.6%5Ctimes%2010%5E%7B-10-1%7D%5C%5C%0Ar%3D5.6%5Ctimes%2010%5E%7B-10%7D%5Ctimes10%5E%7B-1%7D%5C%5C%0Ar%3D%5Cdfrac%7B5.6%5Ctimes%2010%5E%7B-10%7D%7D%7B10%7D%20%5C%5C%0Ar%3D0.56%5Ctimes%2010%5E%7B-10%7D)
Now the base of the exponents of both the atoms are same. As the radius of the nitrogen atom is
meters and the radius of the beryllium atom is
. Thus the radius of beryllium atom is larger.
To calculate how many times, the radius of beryllium atom should be divided by the radius of a nitrogen atom. Thus,
![=\dfrac{1.12\times10^{-10}}{0.56\times10^{-10}} \\ =2](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1.12%5Ctimes10%5E%7B-10%7D%7D%7B0.56%5Ctimes10%5E%7B-10%7D%7D%20%5C%5C%0A%3D2)
Thus the the radius of beryllium atom is larger than the radius of a nitrogen atom by two times.
Learn more about the negative exponents here;
https://brainly.in/question/1221452
Lol i was working on this earlier. First get rid of the parenthesis by distributing the powers to the other powers.
27/4x(6)y(8)
the () are for powers
Easy, just divide
kelly=440mi/8hr=220mi/4hr=110mi/2hr=55mi/1hr
alberto=468mi/9hr=156mi/3hr=52mi/1hr
55>52
kelly drove 55mi in 1 hour
55-52=3
she drove 3 miles more in 1 hour
Answer:
i think it is D bro let me know if i am right okay and can i get branliest if i get it right
Step-by-step explanation:
I need a picture I will answer the question if there is a picture